我有一个主视图控制器。它包含一个表视图控制器(在一个容器中),我想要整理tableview,所以它显示类似于facebook登录一个。
我在viewDidLoad中的子视图控制器(它是一个tableview控制器)中使用的代码:
self.tableView.layer.cornerRadius = 10.0f;
self.tableView.layer.masksToBounds = YES;
self.tableView.clipsToBounds = YES;
self.tableView.backgroundColor = [UIColor clearColor];
结果:
正如您所看到的,当选择该字段时,角落SEEM会圆整,但白色空间仍然存在。即使没有选中它,我怎样才能使它们变圆?
使用:XCODE 5,IOS 7
答案 0 :(得分:3)
正如您要求我做的那样,这是您想要的代码:
for (CALayer *subLayer in self.tableView.layer.sublayers)
{
subLayer.cornerRadius = 10;
subLayer.masksToBounds = YES;
}
答案 1 :(得分:-1)
试试这个
@interface CustomtableViewController : UITableViewController<UITableViewDelegate, UITableViewDataSource>
{
UITextField * username;
UIButton * submit;
}
@implementation CustomtableViewController
- (void)viewDidLoad
{
UIView *newView = [[UIView alloc]initWithFrame:CGRectMake(10, 70, 300, 45)];
submit = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[submit setTitleColor:[UIColor blackColor] forState:UIControlStateNormal];
//[submit setTitleColor:[UIColor colorWithWhite:0.0 alpha:0.56] forState:UIControlStateDisabled];
[submit setTitle:@"Login" forState:UIControlStateNormal];
[submit.titleLabel setFont:[UIFont boldSystemFontOfSize:14]];
[submit setFrame:CGRectMake(10.0, 15.0, 280.0, 44.0)];
[newView addSubview:submit];
[self.tableView setTableFooterView:newView];
[super viewDidLoad];
}
#pragma mark - Table view data source
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
#warning Potentially incomplete method implementation.
// Return the number of sections.
return 1;
}
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
#warning Incomplete method implementation.
// Return the number of rows in the section.
return 2;
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
//self.tableView.contentOffset = CGPointMake( 10, 320);
[self.tableView setContentInset:UIEdgeInsetsMake(50,0,0,0)];
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
}
if ([indexPath section] == 0) {
username = [[UITextField alloc] initWithFrame:CGRectMake(110, 10, 185, 30)];
username.adjustsFontSizeToFitWidth = YES;
username.textColor = [UIColor blackColor];
if ([indexPath row] == 0) {
username.placeholder = @"example@gmail.com";
username.keyboardType = UIKeyboardTypeEmailAddress;
username.returnKeyType = UIReturnKeyNext;
cell.textLabel.text = @"Username";
username.clearButtonMode = YES;
}
else {
username.placeholder = @"minimum 6 characters";
username.keyboardType = UIKeyboardTypeDefault;
username.returnKeyType = UIReturnKeyDone;
username.secureTextEntry = YES;
cell.textLabel.text = @"Password";
username.clearButtonMode = UITextFieldViewModeAlways;
}
username.backgroundColor = [UIColor whiteColor];
username.autocorrectionType = UITextAutocorrectionTypeNo; // no auto correction support
username.autocapitalizationType = UITextAutocapitalizationTypeNone; // no auto capitalization support
username.textAlignment = NSTextAlignmentLeft;
username.tag = 0;
username.clearButtonMode = UITextFieldViewModeAlways; // no clear 'x' button to the right
[username setEnabled: YES];
[cell.contentView addSubview: username];
}
// Configure the cell...
return cell;
}
在这里,我只为用户名和密码创建了两个文本字段。您可以使用else if条件根据需要在每个连续行中插入任何no text文本字段。
- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section {
return [NSString stringWithFormat:@"User Login"];
}
- (CGFloat)tableView:(UITableView *)tableView heightForFooterInSection:(NSInteger)section {
return 50;
}
- (NSString *)tableView:(UITableView *)tableView titleForFooterInSection:(NSInteger)section {
return @"";
}
因此,我的代码仅用于创建包含两个文本字段(用户名和密码)和登录按钮的登录页面。您可以根据需要修改我的代码。干杯!