根据潜在客户的ID将所有注释连接在一行中？

Question

我有一个查询来查找糖块中铅的所有注释。根据屏幕截图，一个主管有3或4个音符。

我想根据潜在客户的ID连接一行（名称列）中的所有注释。

我的查询是，

---

SELECT l.first_name, l.last_name, l.id, n.name, n.description
FROM 
    leads AS l inner join notes as n on l.id = n.parent_id
where l.deleted = 0
and n.deleted = 0
and l.id='104c4b25-adab-32f3-16ee-50d098a5dd5d'

---

Answer 1

您可以使用group_concat()功能

SELECT l.first_name, l.last_name, l.id, group_concat(n.name), n.description
FROM 
    leads AS l inner join notes as n on l.id = n.parent_id
where l.deleted = 0
and n.deleted = 0
and l.id='104c4b25-adab-32f3-16ee-50d098a5dd5d'
group by l.id

Answer 2

您需要使用GROUP_CONCAT 。

在您的情况下，请使用以下语法作为逗号分隔列表：

SELECT l.first_name, l.last_name, l.id, n.name, n.description,
GROUP_CONCAT(n.name SEPARATOR ",") AS notes
FROM 
leads AS l inner join notes as n on l.id = n.parent_id
where l.deleted = 0
and n.deleted = 0
and l.id='104c4b25-adab-32f3-16ee-50d098a5dd5d'
GROUP BY l.id

这是我脑子里打字的，可能需要精炼。