根据R中的单个ID对值行进行分组

时间:2018-08-02 14:50:03

标签: r group-by reshape reshape2

嗨,我有一个像这样的数据框:

> dput(tst_df)
structure(list(Item = c("a", "a", "a", "a", "a", "b", "b", "b", 
"b", "b"), sku = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 
2L, 2L), .Label = c("HOU394386-411", "HOU454800-463"), class = "factor"), 
    ean = structure(1:10, .Label = c("8718476625642", "8718476625659", 
    "8718476625666", "8718476625673", "8718476625680", "8718476630066", 
    "8718476630073", "8718476630080", "8718476630097", "8718476630103"
    ), class = "factor")), .Names = c("Item", "sku", "ean"), row.names = c(NA, 
-10L), class = "data.frame")

我要在sku列上分组并在sku旁边是属于该SKU的eans。

示例:

第1行:

HOU394386-411    8718476625642    8718476625659    8718476625666 8718476625673    8718476625680

第2行:

HOU454800-463    8718476630066    8718476630073    8718476630080 8718476630097    8718476630103

如果我尝试使用group_by并从dplyr包中进行总结或使用reshapes函数强制转换,我将无法获得所需的内容。所有的EANS都成为列,我只希望属于SKU的EAN。这有可能吗?

1 个答案:

答案 0 :(得分:1)

您可以尝试

library(tidyverse)
d %>% 
  group_by(sku) %>% 
  mutate(n=1:n()) %>% 
  select(-Item) %>% 
  ungroup() %>% 
  spread(n, ean) 
# A tibble: 2 x 6
  sku           `1`           `2`           `3`           `4`           `5`          
  <fct>         <fct>         <fct>         <fct>         <fct>         <fct>        
1 HOU394386-411 8718476625642 8718476625659 8718476625666 8718476625673 8718476625680
2 HOU454800-463 8718476630066 8718476630073 8718476630080 8718476630097 8718476630103