请查看以下代码:
class Parent {
Parent() {
printFunction();
}
public void printFunction() {
System.out.println("Parent Print");
}
class ParentInner {
ParentInner() {
InnerPrint();
}
void InnerPrint() {
System.out.println("Parent Inner print");
}
}
}
class Child extends Parent {
ChildInner ci;
Child() {
super();
ci = new ChildInner();
}
@Override
public void printFunction() {
System.out.println("Child Print");
}
class ChildInner extends ParentInner {
ChildInner() {
super();
}
@Override
void InnerPrint() {
System.out.println("Child Inner print");
}
}
public static void main(String[] args) {
Child c = new Child();
}
}
来自Java编译器(eclipse和linux)的此代码的输出是:
Child print
Child Inner print
这在C ++(gcc)
中#include <iostream>
#include <new>
using namespace std;
class Parent {
public:
Parent() {
printFunction();
}
virtual void printFunction() {
cout << "Parent print\n";
}
class ParentInner {
public:
ParentInner() {
InnerPrint();
}
virtual void InnerPrint() {
cout << "Parent Inner print\n";
}
};
};
class Child : public Parent {
public:
Child():Parent() {
ci = new ChildInner();
}
void printFunction() {
cout << "Child print\n";
}
class ChildInner : public ParentInner {
public:
ChildInner():ParentInner() {
}
void InnerPrint() {
cout << "Child Inner print\n";
}
};
ChildInner *ci;
};
int main(int argc, char* argv[]) {
Child *c = new Child();
return 0;
}
打印:
Parent print
Parent Inner print
说什么?我认为基类首先被创建,然后child-gcc是合乎逻辑的。什么是Java?
答案 0 :(得分:0)
这是你怀疑的。从Parent
构造函数初始值设定项列表中调用Child
构造函数时,尚未完全创建Child
对象。所以在某种程度上还没有Child
个对象,只有Parent
对象。