Question

所以我一直在为一个项目开发一个python游戏。我现在遇到了麻烦，如果我在游戏中设置一个障碍，我无法让它像我的照片碰撞时那样回应我的照片，游戏结束。我已经有很长一段时间了，但是我无法弄清楚代码。任何帮助都会非常感激。我非常需要帮助。请注意，我不是初学者，而是刚开始学习python一个月前。所以请尽量理解。我已附上以下代码。

import pygame, random, sys
from pygame.locals import *
BACKGROUNDCOLOR = (181, 230, 29)
FPS = 30
pixels = 5


pygame.init()
mainClock = pygame.time.Clock()
windowSurface = pygame.display.set_mode((990, 557))
pygame.display.set_caption('Clumsy Claire :D')

background = pygame.image.load('grass.jpg')
backgroundRect = background.get_rect()
size = (990, 557)
background.get_size()

image = pygame.image.load('snail 2.png')
imageRect = image.get_rect()

stone1 = pygame.image.load('rock.PNG')
stone1Rect = stone1.get_rect()
stone2 = pygame.image.load('rock.PNG')
stone2Rect = stone2.get_rect()


BROWN =  (128,64,0)
pygame.draw.line(background, BROWN, (98, 555), (98,69), 12)
pygame.draw.line(background, BROWN, (98, 16), (98,1), 12)
pygame.draw.line(background, BROWN, (94, 3), (283, 3),12)
pygame.draw.line(background, BROWN, (278, 457), (278, 3),12)
pygame.draw.line(background, BROWN, (278, 554), (278, 512),12)
pygame.draw.line(background, BROWN, (274, 554), (470, 554),12)
pygame.draw.line(background, BROWN, (465, 554), (465, 90),12)
pygame.draw.line(background, BROWN, (465, 35), (465, 0),12)
pygame.draw.line(background, BROWN, (465, 3), (657, 3),12)
pygame.draw.line(background, BROWN, (652,555 ), (652, 502),12)
pygame.draw.line(background, BROWN, (652, 449), (652, 0),12)
pygame.draw.line(background, BROWN, (648, 553), (844, 553),12)
pygame.draw.line(background, BROWN, (838, 553 ), (838, 138),12)
pygame.draw.line(background, BROWN, (838, 84 ), (838, 0),12)

while True:
    imageRect.topleft = (10,488)
    moveLeft = False
    moveRight = False
    moveUp = False
    moveDown = False

    while True:
        for event in pygame.event.get():
            if event.type == QUIT:
                pygame.quit()
                sys.exit()
            if event.type == KEYDOWN:
                if event.key == K_LEFT:
                   moveLeft = True
                if event.key == K_RIGHT:
                   moveRight = True
                if event.key == K_UP:
                   moveUp = True
                if event.key == K_DOWN:
                   moveDown = True

           if event.type == KEYUP:
               if event.key == K_LEFT:
                    moveLeft = False
               if event.key == K_RIGHT:
                    moveRight = False
               if event.key == K_UP:
                    moveUp = False
               if event.key == K_DOWN:
                    moveDown = False

          if moveLeft and imageRect.left > 0:
              imageRect.move_ip(-1 * pixels, 0)
          if moveRight and imageRect.right < 990:
              imageRect.move_ip(pixels, 0)
          if moveUp and imageRect.top > 0:
              imageRect.move_ip(0, -1 * pixels)
          if moveDown and imageRect.bottom < 557:
              imageRect.move_ip(0, pixels)

          windowSurface.blit(background, backgroundRect)
          windowSurface.blit(image, imageRect)
          rock1 = background.blit(stone1,(658,337))
          rock2 = background.blit(stone2,(225,150))


          pygame.display.update()

          mainClock.tick(FPS)

Answer 1

您需要在代码中添加colliderect函数等。现在你无法测试碰撞。将其粘贴到你的blit代码下面：

if imageRect.colliderect(stone1Rect):
    print('Game Over')
    pygame.quit()
if imageRect.colliderect(stone2Rect):
    print('Game Over')
    pygame.quit()

这段代码：

rock1 = background.blit(stone1,(658,337))
rock2 = background.blit(stone2,(225,150))

也需要更改为：

windowSurface.blit(stone1, (658, 337))
windowSurface.blit(stone2, (225, 150))

我们需要更改上述内容的原因是：您的代码在背景图像上而不是窗口上显示;这是一种不好的做法。

出于某种原因，我猜你正在从inventwithpython.org学习python; D这就是我学习它的方式（如果我猜的是对的; D）

如果您需要更多帮助或有疑问，请在下方发表评论。祝你好运！

python碰撞检测？

1 个答案: