我有一个NSURL:
serverCall X = A&安培; Y = B和Z = C
获得y值的最快捷,最有效的方法是什么?
由于
答案 0 :(得分:79)
<强>更新强>
自2010年撰写本文以来,Apple似乎已经发布了一套用于此目的的工具。请参阅下面的答案。
老派解决方案:
嗯,我知道你说过“最快的方式”,但在我开始用NSScanner
进行测试后,我无法停止。虽然它不是最短的方式,但如果你计划大量使用这个功能,它肯定很方便。我创建了一个URLParser
类,使用NSScanner
获取这些变量。用法很简单:
URLParser *parser = [[[URLParser alloc] initWithURLString:@"http://blahblahblah.com/serverCall?x=a&y=b&z=c&flash=yes"] autorelease];
NSString *y = [parser valueForVariable:@"y"];
NSLog(@"%@", y); //b
NSString *a = [parser valueForVariable:@"a"];
NSLog(@"%@", a); //(null)
NSString *flash = [parser valueForVariable:@"flash"];
NSLog(@"%@", flash); //yes
执行此操作的类如下(*帖子底部的*源文件):
<强> URLParser.h 强>
@interface URLParser : NSObject {
NSArray *variables;
}
@property (nonatomic, retain) NSArray *variables;
- (id)initWithURLString:(NSString *)url;
- (NSString *)valueForVariable:(NSString *)varName;
@end
<强> URLParser.m 强>
@implementation URLParser
@synthesize variables;
- (id) initWithURLString:(NSString *)url{
self = [super init];
if (self != nil) {
NSString *string = url;
NSScanner *scanner = [NSScanner scannerWithString:string];
[scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"&?"]];
NSString *tempString;
NSMutableArray *vars = [NSMutableArray new];
[scanner scanUpToString:@"?" intoString:nil]; //ignore the beginning of the string and skip to the vars
while ([scanner scanUpToString:@"&" intoString:&tempString]) {
[vars addObject:[tempString copy]];
}
self.variables = vars;
[vars release];
}
return self;
}
- (NSString *)valueForVariable:(NSString *)varName {
for (NSString *var in self.variables) {
if ([var length] > [varName length]+1 && [[var substringWithRange:NSMakeRange(0, [varName length]+1)] isEqualToString:[varName stringByAppendingString:@"="]]) {
NSString *varValue = [var substringFromIndex:[varName length]+1];
return varValue;
}
}
return nil;
}
- (void) dealloc{
self.variables = nil;
[super dealloc];
}
@end
*如果你不喜欢复制和粘贴,你可以下载源文件 - 我发了一篇关于这个here的快速博客文章。
答案 1 :(得分:63)
这里有很多自定义网址解析器,请记住 NSURLComponents 是你的朋友!
以下是我为“page”
提取url编码参数的示例<强>夫特强>
let myURL = "www.something.com?page=2"
var pageNumber : Int?
if let queryItems = NSURLComponents(string: myURL)?.queryItems {
for item in queryItems {
if item.name == "page" {
if let itemValue = item.value {
pageNumber = Int(itemValue)
}
}
}
}
print("Found page number: \(pageNumber)")
<强>目标C 强>
NSString *myURL = @"www.something.com?page=2";
NSURLComponents *components = [NSURLComponents componentsWithString:myURL];
NSNumber *page = nil;
for(NSURLQueryItem *item in components.queryItems)
{
if([item.name isEqualToString:@"page"])
page = [NSNumber numberWithInteger:item.value.integerValue];
}
“为什么重新发明轮子!” - 某人智能
答案 2 :(得分:19)
我很确定你必须自己解析它。但是,它并不太糟糕:
NSString * q = [myURL query];
NSArray * pairs = [q componentsSeparatedByString:@"&"];
NSMutableDictionary * kvPairs = [NSMutableDictionary dictionary];
for (NSString * pair in pairs) {
NSArray * bits = [pair componentsSeparatedByString:@"="];
NSString * key = [[bits objectAtIndex:0] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString * value = [[bits objectAtIndex:1] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[kvPairs setObject:value forKey:key];
}
NSLog(@"y = %@", [kvPairs objectForKey:@"y"]);
答案 3 :(得分:11)
在Swift中,您可以使用NSURLComponents将NSURL的查询字符串解析为[AnyObject]。
然后,您可以从中创建字典(或直接访问项目)以获取键/值对。作为一个例子,我正在使用它来解析NSURL变量url:
let urlComponents = NSURLComponents(URL: url, resolvingAgainstBaseURL: false)
let items = urlComponents?.queryItems as [NSURLQueryItem]
var dict = NSMutableDictionary()
for item in items{
dict.setValue(item.value, forKey: item.name)
}
println(dict["x"])
答案 4 :(得分:10)
我一直在使用此类别:https://github.com/carlj/NSURL-Parameters。
它小巧易用:
#import "NSURL+Parameters.h"
...
NSURL *url = [NSURL URLWithString:@"http://foo.bar.com?paramA=valueA¶mB=valueB"];
NSString *paramA = url[@"paramA"];
NSString *paramB = url[@"paramB"];
答案 5 :(得分:4)
您可以使用Google Toolbox for Mac。 它为NSString添加了一个函数,用于将查询字符串转换为字典。
http://code.google.com/p/google-toolbox-for-mac/
它就像一个魅力
NSDictionary * d = [NSDictionary gtm_dictionaryWithHttpArgumentsString:[[request URL] query]];
答案 6 :(得分:4)
这是一个Swift 2.0扩展,提供对参数的简单访问:
$arr_res = $_POST['people']
样本用法:
extension NSURL {
var params: [String: String] {
get {
let urlComponents = NSURLComponents(URL: self, resolvingAgainstBaseURL: false)
var items = [String: String]()
for item in urlComponents?.queryItems ?? [] {
items[item.name] = item.value ?? ""
}
return items
}
}
}
答案 7 :(得分:3)
我写了一个简单的类别来扩展NSString / NSURL,它允许你单独提取URL查询参数或者作为键/值对的字典提取:
答案 8 :(得分:2)
我使用基于@Dimitris解决方案的类别方法
#import "NSURL+DictionaryValue.h"
@implementation NSURL (DictionaryValue)
-(NSDictionary *)dictionaryValue
{
NSString *string = [[self.absoluteString stringByReplacingOccurrencesOfString:@"+" withString:@" "]
stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSScanner *scanner = [NSScanner scannerWithString:string];
[scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"&?"]];
NSString *temp;
NSMutableDictionary *dict = [[[NSMutableDictionary alloc] init] autorelease];
[scanner scanUpToString:@"?" intoString:nil]; //ignore the beginning of the string and skip to the vars
while ([scanner scanUpToString:@"&" intoString:&temp])
{
NSArray *parts = [temp componentsSeparatedByString:@"="];
if([parts count] == 2)
{
[dict setObject:[parts objectAtIndex:1] forKey:[parts objectAtIndex:0]];
}
}
return dict;
}
@end
答案 9 :(得分:0)
我建议查看getResourceValue:forKey:error:
。我相信forKey
参数将为y
。
答案 10 :(得分:0)
你可以这么做:
- (NSMutableDictionary *) getUrlParameters:(NSURL *) url
{
NSMutableDictionary *params = [[NSMutableDictionary alloc] init];
NSString *tmpKey = [url query];
for (NSString *param in [[url query] componentsSeparatedByString:@"="])
{
if ([tmpKey rangeOfString:param].location == NSNotFound)
{
[params setValue:param forKey:tmpKey];
tmpKey = nil;
}
tmpKey = param;
}
[tmpKey release];
return params;
}
它像它一样返回Dictionary:Key = value
答案 11 :(得分:0)
我编辑了Dimitris&#39;稍微代码以获得更好的内存管理和效率。此外,它适用于ARC。
<强> URLParser.h 强>
@interface URLParser : NSObject
- (void)setURLString:(NSString *)url;
- (NSString *)valueForVariable:(NSString *)varName;
@end
<强> URLParser.m 强>
#import "URLParser.h"
@implementation URLParser {
NSMutableDictionary *_variablesDict;
}
- (void)setURLString:(NSString *)url {
[_variablesDict removeAllObjects];
NSString *string = url;
NSScanner *scanner = [NSScanner scannerWithString:string];
[scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"&?"]];
NSString *tempString;
[scanner scanUpToString:@"?" intoString:nil]; //ignore the beginning of the string and skip to the vars
while ([scanner scanUpToString:@"&" intoString:&tempString]) {
NSString *dataString = [tempString copy];
NSArray *sepStrings = [dataString componentsSeparatedByString:@"="];
if ([sepStrings count] == 2) {
[_variablesDict setValue:sepStrings[1] forKeyPath:sepStrings[0]];
}
}
}
- (id)init
{
self = [super init];
if (self) {
_variablesDict = [[NSMutableDictionary alloc] init];
}
return self;
}
- (NSString *)valueForVariable:(NSString *)varName {
NSString *val = [_variablesDict valueForKeyPath:varName];
return val;
return nil;
}
-(NSString *)description {
return [NSString stringWithFormat:@"Current Variables: %@", _variablesDict];
}
@end
答案 12 :(得分:0)
以下将接受的答案作为一个类别:
@implementation NSURL(Parsing)
- (NSString *)valueForParameterWithKey:(NSString *)key {
for (NSString *var in self.parameterKeys) {
if (var.length > key.length+1 && [[var substringWithRange:NSMakeRange(0, key.length+1)] isEqualToString:[key stringByAppendingString:@"="]]) {
NSString *varValue = [var substringFromIndex:key.length+1];
return varValue;
}
}
return nil;
}
- (NSArray<NSString *> *)parameterKeys {
NSScanner *scanner = [NSScanner scannerWithString:self.absoluteString];
[scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"&?"]];
NSString *tempString;
NSMutableArray *vars = [NSMutableArray new];
[scanner scanUpToString:@"?" intoString:nil];
while ([scanner scanUpToString:@"&" intoString:&tempString]) {
[vars addObject:tempString.copy];
}
return vars;
}
@end
答案 13 :(得分:0)
所有当前答案都是特定版本或不必要的浪费。如果你只想要一个值,为什么要创建一个字典?
这是一个支持所有iOS版本的简单答案:
- (NSString *)getQueryParam:(NSString *)name fromURL:(NSURL *)url
{
if (url)
{
NSArray *urlComponents = [url.query componentsSeparatedByString:@"&"];
for (NSString *keyValuePair in urlComponents)
{
NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="];
NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding];
if ([key isEqualToString:name])
{
return [[pairComponents lastObject] stringByRemovingPercentEncoding];
}
}
}
return nil;
}
答案 14 :(得分:-2)
最快的是:
NSString* x = [url valueForQueryParameterKey:@"x"];