NSString *lDownloadURL = [NSString
stringWithFormat:@"https://xxxx.com/tes.php?filename=%@",
tUniqueId]; // tUniqueId=1311454454.4270
NSString *result=
[lDownloadURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(@"Download URL: %@", lDownloadURL);
[helper download:lDownloadURL];
//当我试图传递这个网址时,它会显示以下错误
数据失败:网址无效 [https://xxxx.com/tes.php?filename=1311454454.4270]
请尽快帮助我...提前谢谢
答案 0 :(得分:0)
你的意思是test.php而不是tes.php吗?