Question

我有一个像这样的字符串

((one = WORD) AND (two != 2) AND (three > 3) AND (four >= 4) AND (five < 5) AND (six <= 6) AND (seven IN (seven1, seven2)) AND (eight LIKE 'like'))

我需要一个匹配所有组的模式（Java），注意IN运算符的内部组。我需要这样的结果

one = WORD
two != 2
three > 3
four >= 4
five < 5
six <= 6
seven IN (seven1, seven2)
eight LIKE 'like'

从(到下一个)匹配的单个模式不正常，因为对于IN运算符，有一个内部组

谢谢

Answer 1

使用this page中的模式，我写了这个示例代码

String string = "((one = WORD) AND (two != 2) AND (three > 3) AND (four >= 4) AND (five < 5) AND (six <= 6) AND (seven IN (seven1, seven2)) AND (eight LIKE '1,2,3'))";

long start_time = System.currentTimeMillis();

Pattern pattern = Pattern.compile("\\(([^()]*|\\([^()]*\\))*\\)");
Matcher matcher = pattern.matcher(string);

while (matcher.find())
    System.out.println(matcher.group());

long stop_time = System.currentTimeMillis();
System.out.println("Time " + (stop_time - start_time) + "ms");

输出很完美，但性能令人尴尬，7-8秒

(one = WORD)
(two != 2)
(three > 3)
(four >= 4)
(five < 5)
(six <= 6)
(seven IN (seven1, seven2))
(eight LIKE '1,2,3')

Time 8017ms

编辑：现在已经解决了这个问题

string = string.substring(2, string.length() - 2);
String[] split = string.split("\\) AND \\(");

for (String s : split)
    System.out.println(s);

解析查询SQL-Like以匹配开括号和闭括号

1 个答案: