Question

我在我项目的一个DAO中有这个方法底层RDBMS是MS SQL Server se_subaccountid在数据库级别定义为bigint。

Hibernate返回给我List<BigInteger> 我不想拥有BigInteger对象而是Long对象我怎么能告诉Hibernate给我一个List<Long>？我想在此方法中以编程方式执行此操作，
因为我不希望我的变化产生全球影响这可能吗？怎么样？

@SuppressWarnings({ "rawtypes", "unchecked" })
public List<Long> getAllCheckSubAccounts() {
    Object res = getHibernateTemplate().execute(new HibernateCallback() {
        public Object doInHibernate(Session session) throws HibernateException, SQLException {

            String sql =
                    "select " + 
                    " " + 
                    "distinct sa.se_subaccountid as cid " + 
                    " " + 
                    "from  " + 
                    "subaccount sa  " + 
                    "inner join account a on sa.accountid = a.accountid " + 
                    "inner join product m on sa.mb_id = m.mb_id  " + 
                    "where " + 
                    "(a.se_id = 2) " + 
                    "and " + 
                    "(sa.se_subaccountid is not null)  " + 
                    "and " + 
                    "(m.mb_status not in (128, 512)) " + 
                    "order by  " + 
                    "sa.se_subaccountid asc ";

            SQLQuery query = session.createSQLQuery(sql);
            return query.list();
        }
    });

    return ((List<Long>) res);
}

Answer 1

sess.createSQLQuery("SELECT * FROM CATS")
    .addScalar("cid", StandardBasicTypes.LONG)

类似的主题：
How to specify data type when using native SQL query?

Answer 2

Hibernate从数据库元数据中获取BigInteger。您可以通过以下方式覆盖：

query.addScalar("nextval", LongType.INSTANCE)

Hibernate - 如何以编程方式强制它返回Long而不是BigInteger？

2 个答案: