Question

我试图在C ++中声明一个回调例程，如下所示：

void register_rename (int (*function) (const char *current, const char *new));
    /*------------------------------------------------------------*/
    /* WHEN:  The callback is called once each time a file is received and
     *   accepted.   (Renames the temporary file to its permanent name)
     * WHAT:  Renames a file from the given current name to the specified new name.
     */

但是，我收到以下错误：

line 204: error #70: 
      incomplete type is not allowed
void register_rename (int (*function) (const char *current, const char *new));

我不确定如何纠正这个问题。我在同一个头文件中声明了其他类似的回调例程，我没有收到此错误。

请帮忙！：）

Answer 1

您不能使用new，因为它是关键字。尝试为第二个参数选择一个有效的标识符。

Answer 2

您不能使用保留字命名变量（或任何标识符）;

保留字是关键字

asm do if return try
auto double inline short typedef
bool dynamic_cast int signed typeid
break else long sizeof typename
case enum mutable static union
catch explicit namespace static_assert unsigned
char export **new** static_cast using
class extern operator struct virtual
const false private switch void
const_cast float protected template volatile
continue for public this wchar_t
default friend register throw while
delete goto reinterpret_cast true

和一些运营商的替代名称

and and_eq bitand bitor compl not
not_eq or or_eq xor xor_eq

“不完整类型不允许”错误是什么意思？

2 个答案: