比较mysql中两个相同表之间的行间差异

时间:2014-03-06 11:51:48

标签: mysql compare diff

我有2个相同的表,有不同的数据集,现在我想将单个字段中的单词与表b中同一列的多行进行比较,让我知道每个id的匹配百分比

示例:

以下是表A中的条目

Row1: 1, salt water masala
Row2: 2, water onion maggi milk

以下是表B中的条目

Row1: 1, salt masala water 
Row2: 2, water onion maggi

期望的结果

Row1: Match 100% (All the 3 words are available but different order)
Row2: Match 75%  as 1 word does not match out of the 4 words.

如果有人可以帮助我,那真的很棒。

1 个答案:

答案 0 :(得分:0)

虽然在应用程序代码中实现这一点会更容易,但可以通过几个MySQL函数实现:

delimiter //

drop function if exists string_splitter //
create function string_splitter(
  str text,
  delim varchar(25),
  pos tinyint) returns text
begin
return replace(substring_index(str, delim, pos), concat(substring_index(str, delim, pos - 1), delim), '');
end //

drop function if exists percentage_of_matches //

create function percentage_of_matches(
  str1 text,
  str2 text)returns double
begin
set str1 = trim(str1);
set str2 = trim(str2);
while instr(str1, '  ') do
  set str1 = replace(str1, '  ', ' ');
end while;
while instr(str2, '  ') do
  set str2 = replace(str2, '  ', ' ');
end while;
set @i = 1;
set @numWords = 1 + length(str1) - length(replace(str1, ' ', ''));
set @numMatches = 0;
while @i <= @numWords do
  set @word = string_splitter(str1, ' ', @i);
  if str2 = @word or str2 like concat(@word, ' %') or str2 like concat('% ', @word) or str2 like concat('% ', @word, ' %') then
    set @numMatches = @numMatches + 1;
  end if;
  set @i = @i + 1;
end while;
return (@numMatches / @numWords) * 100;
end //

delimiter ;

第二个函数用在第二个函数中,这是你要在代码中调用的函数,如下所示:

select percentage_of_matches('salt water masala', 'salt masala water');
select percentage_of_matches('water onion maggi milk', 'water onion maggi');