Question

当我运行代码时，它似乎没有在此行

时运行整个main函数

connect_sock = accept(sock, (struct sockaddr *)&serv_name, &len);

就在里面。它甚至不会在开头打印第一个cout，但当我发表评论它工作正常时，有人可以告诉我这个原因吗？

#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <signal.h>
#include <sys/socket.h>
#include <sys/un.h>
#include <netinet/in.h>
#include <iostream>

#define PORT 1227
#define SIM_LENGTH 10;
using namespace std;
void clean_up(int cond, int *sock){
cout<<"exiting";
close(*sock);
exit(cond);
}

int main(void){
cout<<"working;
int sock;
int connect_sock;
struct sockaddr_in serv_name;
size_t len;
int count;

sock =  socket(AF_INET, SOCK_STREAM, 0);
if(sock<0){
cout<<"Error connecting to socket";
clean_up(1, &sock);
}
bzero(&serv_name, sizeof(serv_name)); // set name as physical address
serv_name.sin_family = AF_INET;
serv_name.sin_port = htons(PORT);
if(bind(sock,(struct sockaddr *)&serv_name, sizeof(serv_name))<0){
cout<<"error naming channel";
clean_up(1, &sock);
}
cout<<"waiting for connection from client";
listen(sock, 1);
len = sizeof(serv_name);
connect_sock = accept(sock, (struct sockaddr *)&serv_name, &len);
cout<<connect_sock;
cout<<"server wrote";
close(connect_sock);
cout<<"connect?";
}

Answer 1

正在等待连接。它不会打印第一个cout，因为您没有要求它。尝试：

cout<<"waiting for connection from client"<<endl;

为什么accept（）（用于套接字连接）导致我的代码阻塞？

1 个答案: