Question

在我正在制作的游戏中，我的心底数在底部。当用户触摸“炸弹”时，想法是移除一颗心脏。现在，我在节目的开头创造了所有的心，并将每个人命名为“heart1”“heart2”和“heart3”。在doDamage方法中，当用户触摸炸弹时向hitCount添加1。然后我继续去除心脏。我现在有这个代码。有没有更好，更有效的解决方案呢？ Heere是我现在正在使用的代码。

- (void) doDamage {

    //Sets the isDamaged value to yes and adds a hit point

    isDamaged = YES;
    hitCount++;
    NSLog(@"The hit count is %i ", hitCount);

    //calls the damageDone method after a second to avoid being damaged all the frames the bomb touches the basket
    [self performSelector:@selector(damageDone) withObject:nil afterDelay:0.5];

    //This lengthy code is used to test what heart should be removed each time...

    [self enumerateChildNodesWithName:@"heart1" usingBlock:^(SKNode *node, BOOL *stop){

        //If the hitCount is the same as the heart we want to remove, then we'll remove it from the parent
        if (hitCount == 1) {
            [node removeFromParent];
        }
            }];

    [self enumerateChildNodesWithName:@"heart2" usingBlock:^(SKNode *node, BOOL *stop){

        if (hitCount == 2) {
            [node removeFromParent];
        }
            }];

    [self enumerateChildNodesWithName:@"heart3" usingBlock:^(SKNode *node, BOOL *stop){

        if (hitCount == 3) {
            [node removeFromParent];
        }
            }];
}

Answer 1

我建议隐藏心脏节点而不是移除它们，因为这样你就可以随时带回它们（通电或其他东西）。

SKNode *heartNode;

switch (hitCount)
{

    case 1:
        heartNode = [self childNodeWithName:@"heart1"];
        break;
    case 2:
        heartNode = [self childNodeWithName:@"heart2"];
        break;
    case 3:
        heartNode = [self childNodeWithName:@"heart3"];
        break;

}

if (heartNode)
{
    [heartNode setHidden:TRUE];
}

Answer 2

欣赏这已经有了一个已接受的答案，但如果代码速度很重要，这不会更快......

SKNode *heartNode = [self childNodeWithName:[NSString stringWithFormat:@"heart%d",hitCount]];

[heartNode setHidden:TRUE];

如果heartNode为nil，则setHidden不执行任何操作

不确定stringWithFormat是否比switch声明更快

更有效的代码来测试节点名称

2 个答案: