Question

有两个表：

表1：

 id = 0      name=JOHN           speciality =dentist  
 id = 1      name=ABY            speciality= dentist  
 id = 2      name = SARA         speciality= cardiologist

，...
表2：

 id = 0    name = JOHN           city=paris
 id = 1    name = ABY            city=tokio
 id = 1    name = SARA           city=london

 $city='pa';  

 $speciality='dentist';

（这两个变量来自用户已进入的搜索表单）

我想这样说：

select * FROM Table 1 WHERE speciality=$speciality AND city LIKE %$city% (from Table2) ;

我应该怎么说？（很明显，两个表的每一行的id都相同，每个id代表一个人）

Answer 1

试试这样：

   select t1.* FROM Table 1 as t1,table2 as t2 WHERE t1.speciality='$speciality' AND t1.city  LIKE %$city%  and t1.name=t2.name;

如果两个表的行ID相同，则：

   select t1.* FROM Table 1 as t1,table2 as t2 WHERE t1.speciality='$speciality' AND t1.city  LIKE %$city%  and t1.name=t2.name and t1.id=t2.id ;

如何从具有条件的两个表中进行选择

1 个答案: