Question

表1包括员工姓名及其姓名缩写表2包括projectnumber和pmember（也是首字母）

我们只需要显示员工的名字，所以我必须使用WHERE子句，我无法构建:(这是我到目前为止所做的。它只返回1名员工（正确答案是2名员工））

select t1.name
from t1
where t1.initials IN (select t2.pmember
                     from t2
                     having count(t2.projectnumber) > 1)

提前谢谢！

Answer 1

要显示适用于所有项目的所有emp，您需要这样的独特计数，我认为：

SELECT NAME FROM T1 WHERE INITIALS IN ( 
         SELECT PMEMBER FROM T2 HAVING DISTINCT COUNT(PROJECTNUMBER) = (
             SELECT DISTINCT COUNT(PROJECTNUMBER) FROM T2)
         GROUP BY PMEMBER)

Answer 2

select t1.name
from t1
left join t2 on t1.initials = t2.pmember
group by t1.name
having sum(t2.projectnumber is null) = 0

Answer 3

此查询应该为您提供处理所有项目的成员的名称：

SELECT T1.NAME
  FROM T1
  JOIN T2 ON T1.INITIALS = T2.PMEMBER
 GROUP BY T1.NAME
HAVING COUNT(T2.PROJECTNUMBER) = (SELECT COUNT(1) FROM T2 T2ALIAS)

Answer 4

也许此查询可以帮助您：

SELECT T1.NAME 
FROM T1 
INNER JOIN T2 ON T1.INITIALS = T2.PMEMBER 
HAVING COUNT(T2.PROJECTNUMBER) > 1

显示所有项目的所有员工？

4 个答案: