Question

我取得了一些成功。

类节点可以有多个单元，类单元可以有多个模块。所以，我用这种方式映射我的类：

 Node:


    @Entity
    @Table(name="node")
    @SecondaryTable(name="unit")
    public class Node {
        @Id
        @Column(name = "nid")
        private int nid;
        @Column(name = "nnm")
        private String nnm;
        @Column(name = "nhwtype")
        private int nhwtype;
        @Column(name = "nstate")
        private String nstate;
        @Column(name = "ipaddress")
        private String ipaddress;
        @Column(name = "ipaddressrouterid")
        private String ipaddressrouterid;
        @Column(name = "eswversion")
        private String eswversion;
        @OneToMany
        @JoinColumn(name="nid")
        private Set<Unit> units;

    Unit:

    @Entity
    @Table(name="unit")
    public class Unit {
        @Id
        @Column(name="unnr")
        private int unnr;
        @Column(name="unhwtype")
        private int unhwtype;
        @Column(name="unslot")
        private int unslot;
        @OneToMany
        @JoinColumn(name="unnr")
        private Set<Module> modules;



    Module:

    @Entity
    @Table(name="module")
    public class Module {
        @Id
        @Column(name="mpos")
        private int mpos;
        @Column(name="mhwtype")
        private int mhwtype;

现在hibernate正在创建这样的列表：

列表：

[0] nid 1
     List<Unit> units
       [0] List<Module> modules
[1] nid 1
     List<Unit> units
       [0] List<Module> modules
[2] nid 1
     List<Unit> units
       [0] List<Module> modules

我在节点列表中放置了一个单元列表，并将模块列表放在单元列表中。但是，我正在创建三个相同的索引，我不需要。因为只有一个人拥有我需要的所有信息。另一个问题是某些模块信息不一致。

原因可能是hibernate没有找到where子句正确。这就是为什么它留下了“？”

Hibernate日志：

Hibernate: 
    select
        node0_.nid as nid1_2_,
        node0_.eswversion as eswversi2_2_,
        node0_.ipaddress as ipaddres3_2_,
        node0_.ipaddressrouterid as ipaddres4_2_,
        node0_.nhwtype as nhwtype5_2_,
        node0_.nnm as nnm6_2_,
        node0_.nstate as nstate7_2_ 
    from
        node node0_ 
    left outer join
        unit node0_1_ 
            on node0_.nid=node0_1_.nid //Here it knows 
    where
        node0_.nhwtype in (
            10020 , 10021 , 10022 , 10023 , 10002 , 10017 , 10001
        )
Hibernate: 
    select
        units0_.nid as nid4_2_0_,
        units0_.unnr as unnr1_3_0_,
        units0_.unnr as unnr1_3_1_,
        units0_.unhwtype as unhwtype2_3_1_,
        units0_.unslot as unslot3_3_1_ 
    from
        unit units0_ 
    where
        units0_.nid=? //Here it dont know
Hibernate: 
    select
        modules0_.unnr as unnr3_3_0_,
        modules0_.mpos as mpos1_1_0_,
        modules0_.mpos as mpos1_1_1_,
        modules0_.mhwtype as mhwtype2_1_1_ 
    from
        module modules0_ 
    where
        modules0_.unnr=? //Here it dont know

表节点有一个PK nid。

表单位有一个PK unnr和一个FK nid。

表模块具有PK mpos和FK nid，FK unnr。

Hibernate，正确选择但错误列表

0 个答案: