Grails run-app＆＃34;属性源名称必须包含至少一个字符＆＃34;

Question

当我想使用“grails run-app”启动我的grails应用时，我收到以下消息：

| Running Grails application
| Error 2014-02-25 10:28:12,493 [localhost-startStop-1] ERROR context.GrailsContextLoader  - Error initializing the application: Property source name must contain at least one character
Message: Property source name must contain at least one character
   Line | Method
->> 303 | innerRun in java.util.concurrent.FutureTask$Sync
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 
|   138 | run      in java.util.concurrent.FutureTask
|   895 | runTask  in java.util.concurrent.ThreadPoolExecutor$Worker
|   918 | run      in     ''
^   695 | run . .  in java.lang.Thread

我在干净的系统（Mac OS X）上使用Grails 2.3.4。

如果它有用，这是我的.bash_proifile

export JAVA_HOME=/Library/Java/Home
export PATH="$PATH:$JAVA_HOME/bin"
GRAILS_HOME=/Applications/grails-2.3.4; 
export GRAILS_HOME
PATH=$GRAILS_HOME/bin:$PATH; 
export PATH

该应用程序可在其他4台计算机上完美运行。

Answer 1

此错误文本有时会产生误导。试着把

app.name=MyAppName

进入grails根目录中的application.properties。