if命令使用roman / decimal calculator错误

时间:2014-02-24 13:25:48

标签: python

只打印if中的第二个命令,如果输入为十进制,则不会输出第一个命令。我检查了2个代码分开,他们工作完美。我只想打印十进制,如果它的罗马和罗马,如果它的十进制

roman_to_decimal = { 'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, \
                         'D': 500, 'M': 1000 }
    def int2roman(numberdec):
        numerals={1:"I", 4:"IV", 5:"V", 9: "IX", 10:"X", 40:"XL", 50:"L",
                  90:"XC", 100:"C", 400:"CD", 500:"D", 900:"CM", 1000:"M"}
        result=""
        for value, numeral in sorted(numerals.items(), reverse=True):
            while numberdec >= value:
                result += numeral
                numberdec -= value
        return result


numberchk=(input("Enter a Roman numeral or a Decimal numeral:" ))
  ##here is the problem i get         
if  numberchk==int :
        print (int2roman(int(numberchk)))
        sys.exit()
else :
    roman=numberchk

converted = True
number = 0

for n in range(0, len(roman)-1):
    this_char = roman[n]
    next_char = roman[n+1]
    if (this_char in roman_to_decimal) and \
       (next_char in roman_to_decimal):

        this_number = roman_to_decimal[this_char]
        next_number =  roman_to_decimal[next_char]

        if this_number < next_number:
            number -= this_number
        else:
            number += this_number



if converted:
    ##  add last roman numeral
    number += roman_to_decimal[roman[len(roman)-1]]

    print ("\nThe roman numeral", roman, "is equal to",number)

1 个答案:

答案 0 :(得分:0)

你的行

if  numberchk==int :

似乎不正确。你应该使用

try:
  decval = int(numberchk)
  romanval = int2roman(decval)
  #Continue with other processing here
except ValueError:
  # Verify that it is a legal roman numeral
  romanval = numberchk
  decval = roman2int(numberchk)


# Continue with your processing

print ("\nThe roman numeral", romanval, "is equal to", decval)

可以在以下代码中找到if为false的原因

a = 3
b = ( a == int)
c = type (a)
d = type(int)
print a, b, c, d

输出:     3,False,(类型'int')(类型'type')

这是因为您正在尝试测试值。如果你真的想如图所示测试它,它应该是

type(a) == int:

但是,在您的代码类型(numberchk)中会返回“str”,因为您还没有转换它。这就是为什么你必须使用try:except:method。