尝试实现一个非常简单的Roman Numeral到Decimal转换器,但是如果字符串中有任何非罗马数字字符,似乎无法找到程序返回-1的方法。这是我到目前为止所做的。
#include <stdio.h>
#include <ctype.h>
int convertFromRoman(const char *s)
{
int i = 0;
int total = 0;
while (s[i] != '\0') {
if (isalpha(s[i]) == 0) {
return -1;
}
if (toupper(s[i]) == 'I') {
total += 1;
}
if (toupper(s[i]) == 'V') {
total += 5;
}
if (toupper(s[i]) == 'X') {
total += 10;
}
if (toupper(s[i]) == 'L') {
total += 50;
}
if (toupper(s[i]) == 'C') {
total += 100;
}
if (toupper(s[i]) == 'D') {
total += 500;
}
if (toupper(s[i]) == 'M') {
total += 1000;
} else {
return -1;
}
i++;
}
if (total == 0) {
return -1;
}
return total;
}
int main()
{
printf("%d\n", convertFromRoman("XVII"));
printf("%d\n", convertFromRoman("ABC"));
}
第一个应该返回17,第二个应该返回-1。但是它们都返回-1,但如果我删除else语句,则第一个返回17,第二个返回100.
感谢任何帮助。
答案 0 :(得分:4)
将apply plugin: 'com.android.application'
android {
compileSdkVersion 24
buildToolsVersion "23.0.3"
defaultConfig {
applicationId "com.delbridge.seth.alarm"
minSdkVersion 19
targetSdkVersion 24
versionCode 1
versionName "1.0"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
debug {
debuggable true
}
}
}
dependencies {
compile fileTree(dir: 'libs', include: ['*.jar'])
testCompile 'junit:junit:4.12'
compile 'com.android.support:appcompat-v7:24.1.1'
compile 'com.mcxiaoke.volley:library-aar:1.0.0'
compile 'org.jsoup:jsoup:1.9.2'
compile 'org.jdeferred:jdeferred-android-aar:1.2.4'
compile 'com.google.android.gms:play-services-appindexing:9.4.0'
compile 'com.google.android.gms:play-services:9.4.0'
compile 'com.google.firebase:firebase-ads:9.4.0'
compile 'com.google.android.gms:play-services-ads:9.4.0'
compile 'com.google.android.gms:play-services-auth:9.4.0'
compile 'com.google.android.gms:play-services-gcm:9.4.0'
compile 'com.android.support:support-v4:24.1.1'
compile 'com.android.support:design:24.1.1'
compile 'com.android.support:cardview-v7:24.1.1'
compile 'com.android.support:recyclerview-v7:24.1.1'
}
apply plugin: 'com.google.gms.google-services'
if()
if()
if()
更改为else
if()
else if ()
else if()
else
答案 1 :(得分:2)
不是一个真正的答案,只是一些有趣/另类的方式来看问题。如果你不考虑只是添加“数字”值,它确实解决了这个问题。
char *romanNumerals = "IVXLCDM";
int values[] = { 1, 5, 10, 50, 100, 500, 1000 };
int convertFromRoman(const char *s) {
int val = 0;
for (int i = 0; s[i]; i++) {
char *idx;
if (NULL == (idx = strchr(romanNumerals, toupper(s[i])))) {
return -1;
}
val += values[idx - romanNumerals];
}
return val;
}