Question

我想做一个查询，给我一个累积的所有周数，但是以新月顺序呈现它们，如

Person | Week 1 | Week2 = Week1 + Week2 | Week 3 = Week 1 + 2 + 3|

我的表就像

ID | Week | Person | Item 1 | Item 2 | Item 3 | Iteration

周结果是所有项目的总和，迭代应该是本周的最高数字。

到目前为止，我已达到此目的，但结果并非预期，因为所有行的week1总和相等，这是错误的

SELECT person, w1sum, w2sum
FROM table AS t1, (

SELECT SUM( item1 + item2 + item3 ) AS w1sum
FROM table 
WHERE week =1
AND iteration
IN (

SELECT MAX( iteration ) 
FROM table
)
    GROUP BY person

) AS week1, 
(

SELECT SUM( item1 + item2 + item3 ) AS w2sum
FROM table 
WHERE week = 1 AND week = 2
AND iteration
IN (

SELECT MAX( iteration ) 
FROM table
)
    GROUP BY person

) AS week2

GROUP BY person

Answer 1

我认为你可以使用条件聚合做你想做的事情：

select person,
       sum(case when week in (1) then item1 + item2 + item3 else 0 end) as week1,
       sum(case when week in (1, 2) then item1 + item2 + item3 else 0 end) as week2
       sum(case when week in (1, 2, 3) then item1 + item2 + item3 else 0 end) as week3
from table t
where not exists (select 1
                  from table t2
                  where t2.person = t.person and
                        t2.week = t.week and
                        t2.iteration > t.iteration
                 )
group by person;

where子句获取每周每个人的最后一次迭代。

列匹配的累积和

1 个答案: