Question

这是我的代码，

e.g。 2年，2个月，1周2天，1小时，2分35秒。

    String stdate ="01/01/2014 09:30:30";
    String endate ="09/11/2015 11:30:30";
    SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
    Date d1 = new Date();
    Date d2 = new Date();
    long year =(1000*60*60*24*365l);
    long month =(1000*60*60*24*30l);
    long weeks =(1000*60*60*24*7l);
    long days =(1000*60*60*24l);

    try{

        d1 = df.parse(stdate);
        d2 = df.parse(endate);
        long diff = d2.getTime()-d1.getTime();
        long diffYear = diff/(1000*60*60*24*365l);
        long diffMonth = (diff-(diffYear*year))/month;
        long diffWeeks = ((diff%month))/weeks;
        long diffDays = ((diff%weeks))/days;

        System.out.println(diffYear+" years  ");
        System.out.println(diffMonth+" months ");
        System.out.println(diffWeeks+" week ");
        System.out.println(diffDays+" days "); // wrong output,
    }catch(Exception e){

    }

O / P：

1年 10个月
2周
5天

我不想使用joda时间。它应该在 java.util。*;

中

请提前回复，谢谢。

Answer 1

您可以尝试使用Period

中的Joda-time

String stdate = "01/01/2014 09:30:30";
String endate = "09/11/2015 11:30:30";
SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
Date d1 = df.parse(stdate);
Date d2 = df.parse(endate);;

DateTime startTime = new DateTime(d1), endTime = new DateTime(d2);
Period p = new Period(startTime, endTime);
System.out.printf("%-8s %d %n","years:",p.getYears());
System.out.printf("%-8s %d %n","months:",p.getMonths());
System.out.printf("%-8s %d %n","weeks:",p.getWeeks());
System.out.printf("%-8s %d %n","days:",p.getDays());
System.out.printf("%-8s %d %n","hours:",p.getHours());
System.out.printf("%-8s %d %n","minutes:",p.getMinutes());
System.out.printf("%-8s %d %n","second:",p.getSeconds());

输出：

years:   1 
months:  10 
weeks:   1 
days:    1 
hours:   2 
minutes: 0 
second:  0

更新

回答您的原始问题：就像您从year减去已经属于diff的天数来计算月数一样，您需要减去

用于year和month计算weeks
如果您想计算days

所以你的代码看起来像

long diffYear = diff / year;
long diffMonth = (diff - (diffYear * year)) / month;
//long diffWeeks= ((diff % month)) / weeks;
long diffWeeks = (diff - (diffYear * year + diffMonth * month)) / weeks;
//long diffDays = ((diff % weeks)) / days;
long diffDays = (diff - (diffYear * year + diffMonth * month + diffWeeks*weeks)) / days;//((diff % weeks)) / days;

警告：这种计算天数或周数的方法将每个月视为30天，但并非总是如此，因为也可能有28,29,30,31个月。这就是为什么而不是1天，您会看到5。

警告2 ：对于较大的数字可能导致整数溢出（使用的第一个数字是整数）而不是1000*60*60*24*365l，您应该使用1000L*60*60*24*365。所以

将l更改为L，因为l看起来像1，因此可能会造成混淆，
开始乘以long。

为了方便起见，您甚至可以将其写为

long seconds = 1000L;
long minutes = seconds * 60;
long hours = minutes * 60;
long days = hours * 24;
long weeks = days * 7;
long month = days * 30;
long year = days * 365;

在Java中将时间戳转换为特定格式（年，月，周，日，时，小时，分钟和秒）

1 个答案: