在这里,我只用30天来计算月份,但我想像这样计算月份 这样的1月31日,2月28日或4月30日
我在逻辑上实现了这一目标。请帮我解决这个问题
#include<stdio.h>
void main()
{
int in_days, years, months, days, extra, week;
printf("Enter number of days : ");
scanf("%d", &in_days);
If(in_day>1460){
years = in_days/365;
extra = in_days%365;
months = extra/30;
days = extra%30;
printf("%d days is same as %d years + %d months + %d days", in_days, years, months, days);
}
else If(in_day<1460 & & in_day>=365){
years = in_days/365;
extra = in_days%365;
months = extra/30;
days = extra%30;
printf("%d days is same as %d years + %d months + %d days", in_days, years, months, days);
}
else If(in_day<365){
months = in_day/30;
days = in_day%30;
printf("%d days is same as %d months + %d days", in_days, months, days);
}
else If(in_day<30){
week= in_day/7;
days = week%7;
printf("%d days is same as %d months + %d days", in_days, week, days);
}
getch() ;
}
答案 0 :(得分:0)
您可以添加函数来计算#months
#include<stdio.h>
int cal_months(int *days){
int months_arr[] = {31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365}, i, months = 1;
if(*days < 31){
return 0;
}
for(i = 1; i < 12; i++){
if(*days < months_arr[i]){
*days -= months_arr[i-1];
break;
}else{
months ++;
}
}
return months;
}
int main()
{
int in_days, years, months, days, extra, week;
printf("Enter number of days : ");
scanf("%d", &in_days);
if(in_days>1460){
years = in_days/365;
extra = in_days%365;
months = cal_months(&extra);
//days = extra%30;
printf("%d days is same as %d years + %d months + %d days\n", in_days, years, months, extra);
}else if(in_days<1460 && in_days>=365){
years = in_days/365;
extra = in_days%365;
months = cal_months(&extra);
//days = extra%30;
printf("%d days is same as %d years + %d months + %d days\n", in_days, years, months, extra);
}else if(in_days<365){
days = in_days;
months = cal_months(&days);
printf("%d days is same as %d months + %d days\n", in_days, months, days);
}else if(in_days<31){
week= in_days/7;
days = in_days%7;
printf("%d days is same as %d weeks+ %d days\n", in_days, week, days);
}
return 0;
}
注意:该代码不能处理LEAP年。您应该添加自己的逻辑以包括此功能。