Question

这是一个基于特定算法工作的程序。它在java中完美运行但是每当我运行html代码我都没有得到错误，但它只显示前三个数字，而在java代码中for循环继续，直到显示整数

Java代码

 package test1;

  public class Test1
  {
  public static void main(String arg[])
   {
    int num = 1;
    counterA(num);
  }

  public static void counterA(int num)
   {       
     for (int i = num; i <= 24; i += 5)
     {
        System.out.println(i);
        counterB(i);
     }
 }

 public static void counterB(int i)
 {
    counterA(i * 3);
 }

}

HTML代码

<script>

    var num1 ;
    counterA(num1);
    var total=0;
    var counterA=function(num11)
    {
        for (num1 = num11; num1 <= 24; num1 += 5)
        {
            console.log(num1);
            counterB(num1);
        }

    }

    var counterB =function (num11)
    {
        counterA(num11 * 3);
    }
 </script>

 <body>

<button onclick="counterA(1)">Try it</button>

 </body>

</html>

Answer 1

试试这个，

<!DOCTYPE html>
<html>

<script>

function counterA(num11)
{
   var num1;
    for (num1 = num11; num1 <= 24; num1 += 5)
    {
        alert(num1);
        counterB(num1);
    }
}

function counterB(num11)
{
    counterA(num11 * 3);
}
</script>

<body>

<button onclick="counterA(1)">Try it</button>

</body>

</html>

这给我的输出为1,3,9,14,19,24,8,24,13,18,23,6,18,23,11,16和21。

Answer 2

您的代码中有一些错误：

您在定义函数之前调用它。在counterA定义之前调用它。
您需要重置num1循环

for

使代码生效的可能选项：

移除 var num1 ; counterA(num1); var total=0;
将for (num1 = num11; ...替换为for(var num1 = num11; ...

Answer 3

你可以做到

<html>
<script type="text/javascript">
    function counterA(num11){
        for (var num1 = num11; num1 <= 24; num1 += 5) {
            alert(num1);
            counterA(num1*3);
        }
    }
</script>

<body>
    <button onclick="counterA(1)">Try me</button>
</body>

</html>

我无法将此java代码转换为javascript

}

3 个答案: