IntelliSense：“void”类型的值不能分配给“double”类型的实体

Question

所以，我删除并重新输入了错误引用的行，关闭并重新打开了visual studio，并查看了这里发布的几个与我的相同/相似措辞的错误。

我感觉这是视觉工作室的一个错误，因为即使在我删除了所有代码，保存和重新编译的内容之后，它也会在不再存在的同一行上出错。

  

“IntelliSense：类型为”void“的值无法分配给”double“类型的实体”

为了防止它与工作室的错误，我想我会问我的代码中可能导致此错误的任何想法？代码中间的blockquote是它引用该错误的行。

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int main ()
{
   //Declarations of vectors and basic holders for input transfer
   vector<string> candidateName;
   string inputString;
   vector<int> candidateVotes;
   int counter,inputInt,totaledVotes;
   double percentage;
   vector<double> candidatePercentage;
   //Method declaration for calculations
   void calculatePercentage (int, int, int);

   //User input to gather number of candidates, names, and votes received.
   cout <<"How many candidates need to be input?";
   cin>>counter;
   for(int i = 0;i<counter;i++)
   {
      cout<<"Please enter the candidate's last name.";
      cin>>inputString;
      candidateName.push_back(inputString);
      cout<<"Please enter the number of votes "<<candidateName[i]<<" received.";
      cin>>inputInt;
      candidateVotes.push_back(inputInt);
      totaledVotes+=candidateVotes[i];
   }
   for(int i = 0;i<counter;i++)
   {
      //Problem here vvv
      percentage = calculatePercentage(totaledVotes, candidateVotes[i], i);
      //Problem there ^^^

      candidatePercentage.push_back(percentage);
   }
}

double calculatePercentage (int totalVotes, int candidateVotes, int rosterNumber)
{
   int percentage;
   percentage = candidateVotes/totalVotes;
   percentage*=100;
   return percentage;
}

Answer 1

你有这个声明

void calculatePercentage (int, int, int);

然后你做

percentage = calculatePercentage(totaledVotes, candidateVotes[i], i);

但你刚宣布该函数没有返回任何内容。

它也与以后的实际定义不符：

double calculatePercentage (int totalVotes, int candidateVotes, int rosterNumber)

Answer 2

您声明函数返回void：

void calculatePercentage (int, int, int);

应该{​​{1}}以匹配后面的定义和用法。