Question

我有这个非常简单的xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<ConfigurationFile>
    <ConfigurationFilePath>Test1</ConfigurationFilePath>
    <ConnectionString>Test2</ConnectionString>
    <AnalyzeFilePath>Test3</AnalyzeFilePath>
</ConfigurationFile>

我想获得每个领域的信息。但这并没有显示任何东西......

这是我的C＃代码：

private void ParseXMLFile()
{
    Console.WriteLine("Parse");
    if (configurationPAthFileTextbox.Text != null)
    {
        Console.WriteLine("file != null");
        try
        {
            XElement main = XElement.Load(configurationPAthFileTextbox.Text);

            var results = main.Descendants("ConfigurationFile")
                          .Select(e => new { ConfigurationFilePath = e.Descendants("ConfigurationFilePath").FirstOrDefault().Value,
                                   ConnectionString = e.Descendants("ConnectionString").FirstOrDefault().Value });

            foreach (var result in results)
                Console.WriteLine("{0}, {1}", result.ConfigurationFilePath, result.ConnectionString);
            Console.ReadLine();

        }
        catch (Exception e)
        {
            Debug.WriteLine(e.ToString());
        }
    }
}

Answer 1

将其加载为XDocument，因为它是文档，而不是元素。
```
var xDoc = XDocument.Load(configurationPAthFileTextbox.Text);
```

您可以轻松地将文档转换为Dictionary<string, string>，其中元素名称为键，元素值为值：

var results = xDoc.Root
                  .Elements()
                  .ToDictionary(e => e.Name, e => (string)e);

打印ConfigurationFilePath和ConnectionString：

Console.WriteLine("{0}, {1}", results["ConfigurationFilePath"], results["ConnectionString"]);

打印Test1, Test2。

Answer 2

首先，创建一个类来表示XML文件中包含的感兴趣的信息。定义一个构造函数，从XML文件中提取感兴趣的值，并将它们映射到类的属性：

public class ConfigurationFile
{
    public String ConfigurationFilePath { get; set; }
    public String ConnectionString { get; set; }
    public String AnalyzeFilePath { get; set; }

    public ConfigurationFile(String xmlFilePath)
    {
        XDocument document = XDocument.Load(xmlFilePath);
        var root = document.Root;

        ConfigurationFilePath = (string)root.Element("ConfigurationFilePath");
        ConnectionString = (string)root.Element("ConnectionString");
        AnalyzeFilePath = (string)root.Element("AnalyzeFilePath");
    }
}

使用特殊构造函数创建此类后，使用该类非常简单：

var configFile = new ConfigurationFile(xmlFilePath);

var path = configFile.ConfigurationFilePath;
var connectString = configFile.ConnectionString;
var analyzeFilePath = configFile.AnalyzeFilePath;

这是一个将所有内容组合在一起的演示程序。（请注意，在此演示程序中，构造函数从字符串而不是文件中加载XML，如上所示。）

using System;
using System.Xml;
using System.Xml.Linq;

class LinqToXmlDemo
{
    static public void Main(string[] args)
    {
        string xmlContent = GetXml();
        var configFile = new ConfigurationFile(xmlContent);

        Console.WriteLine
            ("ConfigurationFilePath:[{0}]\n" +
             "ConnectionString:[{1}]\n" +
             "AnalyzeFilePath:[{2}]\n--",
             configFile.ConfigurationFilePath,
             configFile.ConnectionString,
             configFile.AnalyzeFilePath);
    }

    static string GetXml()
    {
        return
            @"<?xml version='1.0' encoding='UTF-8'?>
              <ConfigurationFile>
                  <ConfigurationFilePath>Test1</ConfigurationFilePath>
                  <ConnectionString>Test2</ConnectionString>
                  <AnalyzeFilePath>Test3</AnalyzeFilePath>
              </ConfigurationFile>";
    }
}

public class ConfigurationFile
{
    public String ConfigurationFilePath { get; set; }
    public String ConnectionString { get; set; }
    public String AnalyzeFilePath { get; set; }

    public ConfigurationFile(String xml)
    {
        XDocument document = XDocument.Parse(xml);
        var root = document.Root;

        ConfigurationFilePath = (string)root.Element("ConfigurationFilePath");
        ConnectionString = (string)root.Element("ConnectionString");
        AnalyzeFilePath = (string)root.Element("AnalyzeFilePath");
    }
}

预期输出

ConfigurationFilePath:[Test1]
ConnectionString:[Test2]
AnalyzeFilePath:[Test3]
--

Answer 3

简单地说，您也可以使用：

string yourString = (string)(from element in xDocument.Root.Descendants("ConfigurationFilePath") select element).First();

= d

C＃使用LINQ解析简单的XML文件

3 个答案: