Question

使用simplexml_load_file方法解析XML时遇到问题。我有像这样的xml：

<root>
    <show>
        <list>
            <entry name="this is title" code="1234">
                <infos count="4">
                    <info type="random" percent="10" />
                    <info type="random" percent="12" />
                    <info type="random" percent="13" />
                    <info type="random" percent="15" />
                </infos>
            </entry>
            <entry name="this is titles" code="1235">
                <infos count="4">
                    <info type="random" percent="14" />
                    <info type="random" percent="16" />
                    <info type="random" percent="17" />
                    <info type="random" percent="18" />
                </infos>
            </entry>
        </list>
    </show>
</root>

我尝试使用simplexml_load_file进行解析，但我得到一个结果。我的意思是，不是两个条目。请看下面的代码。

<?php
$url = "text.xml";

$xml = simplexml_load_file($url);

foreach ($xml->show->list as $entry) {
$name = $entry->entry['name'];
$code = $entry->entry['code'];

echo "<p>The List Name: ".$name."</p>";
echo "<p>Code:".$code."</p>";
}
?>

好的，我尝试使用该代码，我只得到一个结果。我不知道怎么循环。所以，我试图在这个网站上提问。

如何完全按照xml循环结果。
使用

感谢所有能够伸出援手的人：D

Answer 1

foreach ($xml->list->enrty as $entry) {
    $name = $entry->entry['name'];
    $code = $entry->entry['code'];

    echo "<p>The List Name: ".$name."</p>";
    echo "<p>Code:".$code."</p>";
}

应该是

foreach ($xml->show->list->entry as $entry) {
    $name = $entry->attributes()->name;
    $code = $entry->attributes()->code;
    //or like this
    //$name = $entry["name"];
    //$name = $entry["code"];
    echo "<p>The List Name: ".$name."</p>";
    echo "<p>Code:".$code."</p>";
}

PHP的简单XML加载文件

1 个答案: