Question

嘿所以我正在使用FTS3和Sqlite来更快地搜索我的Android应用程序，但是，当我编辑一个单词或删除一个单词时，它在我的真实数据库上运行正常，但在FTS上，没有任何反应。

当我搜索名称预编辑/更新或删除后，它仍然显示出它在数据库中的含义......

不确定有什么问题，或者我是否需要以不同的方式解决问题，这是我的代码：

/*
     * deleting all words from dictionary
     */
    public void deleteAllWords(DatabaseWords db_delete) {
        Log.d("enter delete in dbhelper",
                "enter delete in dbhelper "
                        + String.valueOf(db_delete.get_id()));
        SQLiteDatabase db = this.getWritableDatabase();
        db.delete(TABLE_WORDS, KEY_DICTIONARYID + "=?",
                new String[] { String.valueOf(db_delete.get_dictionaryId()) });
    }

    /*
     * deleting all words FTS from dictionary
     */
    public void deleteAllWords_fts(DatabaseWordsFTS db_delete) {
        SQLiteDatabase db = this.getWritableDatabase();
        db.delete(
                TABLE_WORDS_FTS,
                KEY_DICTIONARY_ID_FTS + "=?",
                new String[] { String.valueOf(db_delete.get_dictionary_id_fts()) });
    }

    /*
     * 
     * 
     * /* deleting a dictionary
     */
    public void deleteDictionary(DatabaseDictionary dictionary) {
        SQLiteDatabase db = this.getWritableDatabase();
        db.delete(TABLE_DICTIONARY, KEY_ID + "=?",
                new String[] { String.valueOf(dictionary.get_id()) });
    }

    /*
     * deleting a word
     */
    public void deleteWord(DatabaseWords db_delete) {
        Log.d("enter delete in dbhelper",
                "enter delete in dbhelper "
                        + String.valueOf(db_delete.get_id()));
        SQLiteDatabase db = this.getWritableDatabase();
        db.delete(TABLE_WORDS, KEY_ID + "=?",
                new String[] { String.valueOf(db_delete.get_id()) });
    }

    /*
     * deleting a word FTS
     */
    public void deleteWord_fts(DatabaseWordsFTS db_delete) {
        SQLiteDatabase db = this.getWritableDatabase();
        db.delete(TABLE_WORDS_FTS, KEY_ID + "=?",
                new String[] { String.valueOf(db_delete.get_id()) });
    }

/*
     * updating a word
     */
    public int updateWord(DatabaseWords word) {
        SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_DICTIONARYID, word.get_dictionaryId());
        values.put(KEY_WORD1, word.get_word1());
        values.put(KEY_WORD2, word.get_word2());
        values.put(KEY_WORD3, word.get_word3());
        values.put(KEY_WORD4, word.get_word4());

        // updating row
        return db.update(TABLE_WORDS, values, KEY_ID + "=?",
                new String[] { String.valueOf(word.get_id()) });

    }

    /*
     * updating a word FTS
     */
    public int updateWord_fts(DatabaseWordsFTS word_fts) {
        SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_DICTIONARY_ID_FTS, word_fts.get_dictionary_id_fts());
        values.put(KEY_WORD1_FTS, word_fts.get_word1_fts());
        values.put(KEY_WORD2_FTS, word_fts.get_word2_fts());
        values.put(KEY_WORD3_FTS, word_fts.get_word3_fts());
        values.put(KEY_WORD4_FTS, word_fts.get_word4_fts());

        // updating row
        return db.update(TABLE_WORDS_FTS, values, KEY_ID + "=?",
                new String[] { String.valueOf(word_fts.get_id()) });

    }

我将常规的一个放在顶部，有效，FTS的一个是FTS。

在这里，我添加了活动文件

中的更新代码

// store in db
            // creating word
            DatabaseWords db_update = new DatabaseWords(word_id, word_d_id,
                    w_1_s, w_2_s, w_3_s, w_4_s);

            DatabaseWordsFTS db_w_fts = new DatabaseWordsFTS(word_id,
                    word_d_id, w_1_s, w_2_s, w_3_s, w_4_s);
            // insert into db create method in database helper
            db.updateWord(db_update);

            db.updateWord_fts(db_w_fts);

单词更新但是fts one没有？

Answer 1

您无法使用where子句中的数值查询/更新/删除FTS表中的行。它仅适用于文本。但是可以将其转换为数字：

SELECT * FROM fts_table WHERE CAST(id AS NUMERIC) = 69

Sqlite Android数据库没有为FTS更新或删除？

1 个答案: