Question

我已经反序列化了一个xml文件，其中包含程序列表，日期，时间以及对它们的真或假值。该文件类似于下面的内容。

<AlarmSettings xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ProgramSettings>
    <ProgramSetting>
      <ProgramPathText>Alarm.exe</ProgramPathText>
      <ProgramPathValue>D:\Documents\Work\Visual Studio\WindowsFormsApplication1\bin\Debug\Alarm.exe</ProgramPathValue>
      <Monday>
        <Time>11:08</Time>
        <Enabled>true</Enabled>
      </Monday>
      <Tuesday>
        <Time>17:08</Time>
        <Enabled>true</Enabled>
      </Tuesday> 
    </ProgramSetting>
  </ProgramSettings>
</AlarmSettings>

我正在尝试访问这些值，但我一直在程序设置结束时卡住，我无法看到任何有用的方法。我需要返回programpathtext值，programpathvalue值等。

public void load()
{
     AlarmSettings alarmSettings;
     alarmSettings = AlarmSettings.Load(@"C:\Users\jason\Desktop\Booya.txt");

     alarmSettings.ProgramSettings.
}

任何帮助将不胜感激。感谢

AlarmSettings Class

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Serialization;
using System.IO;
namespace WindowsAlarm
{
    public class AlarmSettings
    {
        public List<ProgramSetting> ProgramSettings = new List<ProgramSetting>();


        public void Save(string filename)
        {
            XmlSerializer serializer = new XmlSerializer(typeof(AlarmSettings));
            TextWriter writer = new StreamWriter(filename);


            serializer.Serialize(writer, this);
            writer.Close();
        }

        public static AlarmSettings Load(string filename)
        {
            try
            {
                XmlSerializer serializer = new XmlSerializer(typeof(AlarmSettings));
                using (StreamReader reader = new StreamReader(filename))
                {
                    AlarmSettings loadedSettings = (AlarmSettings)serializer.Deserialize(reader);

                    reader.Close();

                    return loadedSettings;

                }
            }
            catch(Exception e)
            {
                throw e;
                //return new AlarmSettings();
            }
        }
    }
}

Answer 1

如果你有适当的对象结构，请使用XmlSerializer

XmlSerializer serializer = new XmlSerializer(typeof(objecttype));

或使用Linq to XML或创建自己的XML解析器，你可以在Google上搜索

您还可以查看有关序列化的帖子：Object to XML using LINQ or XmlSerializer

Answer 2

我已经解决了这个问题。问题是我没有进入并访问该集合。

        public void load()
    {
        AlarmSettings alarmSettings;
        alarmSettings = AlarmSettings.Load(@"C:\Users\jason\Desktop\Booya.txt");

        foreach (var setting in alarmSettings.ProgramSettings)
        {
            string pathtext = setting.ProgramPathText;
            string pathvalue = setting.ProgramPathValue;
        }

    }

获得反序列化的值

2 个答案: