Question

我正在参加一场比赛，让每个战斗机对抗另外5名战士。为此，我有两个数组，playerArray和opponentArray，每个数组包含相同的六种字符类型。

在锦标赛中进行匹配时，我想阻止他们对抗自己的类型，例如，我不想让Rogue与Rogue对战。

这是用splice以某种方式完成的吗？

var playerArray:Array = ["Fighter", "Ranger", "Wizard", "Rogue", "Cleric", "Sorcerer"];
var opponentArray:Array = ["Fighter", "Ranger", "Wizard", "Rogue", "Cleric", "Sorcerer"];

charSel.addEventListener(MouseEvent.CLICK, matchups);

function matchups(event:MouseEvent){
for (a = 0; a < 6; a++){        // for each character
    trace ("\n=== " + playerArray[a] + " fights ===\n");
    for (b = 0; b < 5; b++){    // fight each opponent
        trace (playerArray[a] + " vs " + opponentArray[b]);
    }
}

}

全新的。谢谢你的帮助！

Answer 1

使用字符串比较作为快速解决方案，

我已更新您的代码，

function matchups(event:MouseEvent) {

   for (a = 0; a < 6; a++){  // for each character

        trace ("\n=== " + playerArray[a] + " fights ===\n");

        for (b = 0; b < 5; b++) {    // fight each opponent

            trace (playerArray[a] + " vs " + opponentArray[b]);

            //This is added part (Comparing a String)
            if(String(playerArray[a]) == String(opponentArray[b]))
            {
                  trace("Opponents are of same type.");
            }
        }
    }
}

Answer 2

for (a = 0; a < playerArray.length; a++){        // for each character
    trace ("\n=== " + playerArray[a] + " fights ===\n");
    for (b = 0; b < opponentArray.length; b++){    // fight each opponent
        if(playerArray[a] != opponentArray[b])
            trace (playerArray[a] + " vs " + opponentArray[b]);
    }
}

您可以避免硬编码部分。而是使用array.length属性。

Answer 3

如果playerArray和opponentArray值在迭代中相同，则跳过。

for (var a = 0; a < 6; a++)
{        
    trace ("\n=== " + playerArray[a] + " fights ===\n");

    for (var b = 0; b < 6; b++) //Note here 5 to 6 better you length property of Array like opponentArray.length
    {    
        if(playerArray[a] == opponentArray[b])
            continue;

        trace (playerArray[a] + " vs " + opponentArray[b]);
    }
}

从对应项中排除数组项

3 个答案: