Question

我在PHP中显示表时遇到问题。我已经安装了shortcode exec php插件。

这是我所做的代码：

if(mysql_num_rows($raw_results) > 0){ 

            while($results = mysql_fetch_array($raw_results)){

                echo "<p><h3>".$results['id']."</h3>"."Student Name :".$results['name']."    </p>" . "</br>";
                echo "Age : ".$results['age']." Years old.</br>";
                echo "Course : ".$results['course']."</br>";
                echo "Gender : ".$results['gender']."</br></br>";
                echo "<HR>";

            }
        }

我可以知道如何在表格中对数据进行排序吗？我尝试的任何表格代码似乎都没有显示..

Answer 1

<table>
<tr>
    <td>Student name</td>
    <td>Age</td>
    <td>Course</td>
    <td>Gender</td>
</tr>
<?php
if(mysql_num_rows($raw_results) > 0){ 
        while($results = mysql_fetch_array($raw_results)){
            echo "<tr><td>".$results['id']."</td>";
            echo "<td>".$results['age']."</td>";
            echo "<td>".$results['course']."</td>";
            echo "<td>".$results['gender']."</td></tr>";
        }
    }
?>
</table>

php中的数组排序 http://us1.php.net/manual/en/function.sort.php

Answer 2

简单地回显html表标签，如下所示：

echo "<table border='1'>
<tr>
<th>Id</th>
<th>Age</th>
<th>Course</th>
<th>Gender</th>
</tr>";

while($row = mysqli_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['id'] . "</td>";
  echo "<td>" . $row['name'] . "</td>";
  echo "<td>" . $row['course'] . "</td>";
  echo "<td>" . $row['age'] . "</td>";
  echo "</tr>";
  }
echo "</table>";

Answer 3

    <table>
        <tr>
        <th>ID</th>
        <th>Student Name</th>
        <th>Age</th>
        <th>Course</th>
        <th>Gender</th>
        </tr>

    while($results = mysql_fetch_array($raw_results)){
            echo "<tr>";
            echo "<td>".$results['id']."</td>";
            echo "<td>".$results['name']."</td>";
            echo "<td>".$results['age']." Years old.</td>";
            echo "<td>".$results['course']."</td>";
            echo "<td>".$results['gender']."</td>";
            echo "</tr>";

        }
    echo "</table>";

Answer 4

您需要连接数据库，然后将数据提取到数据库

function onSubmit(e){
var sheet = e.range.getSheet();
var ss = sheet.getParent();
var form = FormApp.openByUrl(ss.getFormUrl());
// Choose destination sheet according to Select the worker:
var destSheet = getSheet(ss, e.namedValues['Select The Worker:']);
// Store the current response in destination sheet
destSheet.appendRow(e.values);

/**
 * Get the sheet with given name. Create sheet if it doesn't exist.
* New sheet will be created with optional headings, if provided.
*
* From: 
*
* @param {Spreadsheet} spreadsheet   Google Spreadsheet object.
* @param {String}      sheetName     Sheet name to get.
* @param {String[]}    headings      Optional array of headings (for new sheet).
*
* @returns {Sheet}                   Sheet object.
*/
function getSheet( spreadsheet, sheetName, headings ) {
 spreadsheet = SpreadsheetApp.getActive();
 var sheet = spreadsheet.getSheetByName(sheetName);
 if (sheet == null) {
  // Not found, so add new sheet
  sheet = spreadsheet.insertSheet(sheetName);
  if (headings && headings.constructor === Array) {
   sheet.getRange(1,1,1,headings.length).setValues([headings]);
 }
}

return sheet;
 }
}

如何在PHP中显示表中的数据

4 个答案: