Question

我有以下表格

作者

id | author_name | author_detail | author_bio

书

id | author_id | book_name | book_detail

我希望以下列方式显示数据

Author Name ::
Author Detail ::
books :: 1.book1
         2.book2
         3.book3
         4.book4

我尝试了以下查询，但根据我的要求没有工作

select * from authors left join books  on author.id=books.author_id

我已经尝试了群组连续但是它给了coma seperate的书名。所以我想要在数组中预订详细信息

 select author.author_name,author.author_detail,author.author_bio,group_concat(books.book_name) eft join books  on author.id=books.author_id

我正在考虑输出

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => Norm

            [books] => Array
                (
                  [0] =>Array
                    (
                    [id] => 4
                    [book_name] => great wall
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )

                    [1] =>Array
                    (
                    [id] => 6
                    [book_name] =>new book
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )
                )
        )
    [1] => Array
        (
            [id] => 2
            [name] => Norm

            [books] => Array
                (
                  [0] =>Array
                    (
                    [id] => 2
                    [book_name] => amazing star
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )

                    [1] =>Array
                    (
                    [id] => 3
                    [book_name] =>way of journy
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )
                )

        )

我也检查了这个问题

displaying php mysql query result with one to many relationship

任何人都可以帮我如何显示上面的数据吗？谢谢

Answer 1

试试这个：

SELECT 
A.id
A.author_name, 
A.author_detail,
A.author_bio,
B.book_name,
B.created_at,
B.updated_at
FROM books AS B
LEFT JOIN author AS A
ON (A.id=B.author_id)

你会得到这样的结果：

id | author_name | author_detail | author_bio | book_name
1  | ari         | some detail   | some bio   | book_ari_1
1  | ari         | some detail   | some bio   | book_ari_2
1  | ari         | some detail   | some bio   | book_ari_3
2  | tester      | some detail   | some bio   | book_tester_1
etc..

要使数组成为您期望的结果，您需要重构数组结果。我将假设您的结果数组将在$result变量

中

$new_result = array();
foreach ($result as $key => $value) {
    if (empty($new_result[$value['id']]))
    {
        $new_result[$value['id']] = array(
            'id' => $value['id'],
            'name' => $value['name'],
            'books' => array(
                array(
                    'id' => $value['id'],
                    'book_name' => $value['book_name'],
                    'created_at' => $value['created_at'],
                    'updated_at' => $value['updated_at']
                ),
            )
        )
    }
    else
    {
        $new_result[$value['id']]['id'] = $value['id'];
        $new_result[$value['id']]['name'] = $value['name'];
        $new_result[$value['id']]['books'][] = array(
            'id' => $value['id'],
            'book_name' => $value['book_name'],
            'created_at' => $value['created_at'],
            'updated_at' => $value['updated_at']
        );
    }
}

the result will look like your expected. but the key number will be formated as id.

重置$new_result的密钥作为增量编号，只需使用值array_values()函数

 $new_result = array_values($new_result);

Answer 2

您可以使用第一个查询来执行此操作...但您必须检查记录循环内的author_id，并仅在值更改时显示作者详细信息（通过将其与存储在变量中的值进行比较））...否则只显示书的详细信息。

所以你的代码可能（非常粗略地）看起来像这样：

  public void addData()
{
     ListSerialPorts listSerPortObj = new ListSerialPorts();



   listData = listSerPortObj.LoadComPorts2();
    for (int index = 0; index < listData.size(); index++)
    {
         str = (String) listData.get(index);
         System.out.println(str);               
         jComboBox2.addItem(str);
   }

更简单（虽然稍长）的方法是进行第二次查询：子查询。它将通过第一个（外部）查询的结果在循环内部发生。因此，您的外部查询将获得作者，并且在您显示作者详细信息之后，您将对作者的书籍进行单独查询...并且您在外部循环中有一个循环来显示每本书的详细信息。

所以你的代码（非常粗略）看起来像这样：

$query = "select whatever whatever...";
$records = $database->Execute($query);
foreach ($records as $fields) {
    if ($fields['id'] != $previous_id) echo "Author ...";
    echo "Book whatever whatever ...";
    $previous_id = $fields['id'];
}

Answer 3

你可以在php中执行此操作，无需进入查询本身，但在单独的查询中获取两个数据，即书籍和作者数据

请记住，我假设$result为作者数据，$result2为图书数据

$item=array();
    while($row=mysql_fetch_array($result))
    {
        $id=$row['id'];        
        $item[$id]['name']=$row['name'];
        $item[$id]['id']=$row['id'];
        $item[$id]['books']=array();
        $temp=array();
        while($row1=mysql_fetch_array($result2))
         {
           if($id==$row1['author_id'])
           {
             $temp['id']=$row1['id'];
             $temp['book_name']=$row1['book_name'];
             $temp['created_at']=$row1['created_at'];
             $temp['updated_at']=$row1['updated_at'];
             array_push($item['id']['books'],$temp);
           }           
         }
    }

现在这里的id被格式化为作者的id。要获得类似的数组键，您可以使用array_values($item)

以Php显示两个表数据

3 个答案: