Question

跟进我的问题yesterday

我有一个table1

Remark    Name  Points
----------------------
Cameroon  SS    10
Cameroon  JL    10
NZ        JL    30

我想将其显示为

       NZ   Cameroon
---------------------
 JL    10      10
 SS     0      30

备注中table1的条目是动态的，将添加更多条目。

我在Php中尝试的是

$query_get = "SELECT DISTINCT remark FROM table1";
$result =  mysql_query($query_get) or die(mysql_error());
$remarks ='';
while ($row = mysql_fetch_array( $result )) {
$remarks .= ",SUM( IF( remark={$row[0]}, 1, 0 ) ) as {$row[0]} ";
};


$query = "SELECT name, .$eventcodes. FROM jr_event_points";
$result1 = mysql_query($query) or die(mysql_error());

现在错误来自查询。一旦我有动态列总结，我应该如何进行第二次查询？

Answer 1

您可以在MySQL端使用动态SQL

执行此操作

SET @sql = NULL;

SELECT GROUP_CONCAT(DISTINCT CONCAT('COALESCE(SUM(CASE WHEN remark = ''', 
                                    remark, 
                                    ''' THEN points END), 0) `',
                                    remark,
                                    '`'))
  INTO @sql
  FROM table1;

SET @sql = CONCAT('SELECT name, ', @sql, ' FROM table1 GROUP BY name');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

输出：

| NAME | CAMEROON | NZ |
|------|----------|----|
|   JL |       10 | 30 |
|   SS |       10 |  0 |

这是 SQLFiddle 演示

如果我想通过php来实现它，是否可能？

$sql = "
SELECT GROUP_CONCAT(DISTINCT CONCAT('COALESCE(SUM(CASE WHEN remark = ''', 
                                    remark, 
                                    ''' THEN points END), 0) `',
                                    remark,
                                    '`')) columns
  FROM table1";
$result = mysql_query($sql);
if (!$result) {
    die ('Error: ' . mysql_error()); //TODO: better error handling
}
$row = mysql_fetch_assoc($result);
$sql = "SELECT name, {$row['columns']} FROM table1 GROUP BY name";
$result = mysql_query($sql);
if (!$result) {
    die ('Error: ' . mysql_error()); //TODO: better error handling
}
$row = mysql_fetch_assoc($result);
echo '| '. implode(' | ', array_keys($row)) . ' |' . PHP_EOL;
echo '| '. implode(' | ', array_values($row)) . ' |' . PHP_EOL;
while ($row = mysql_fetch_assoc($result)) {
    echo '| '. implode(' | ', array_values($row)) . ' |' . PHP_EOL;
}

输出：

| name | Cameroon | NZ |
| JL | 10 | 30 |
| SS | 10 | 0 |

注意：考虑从mysql_*切换到mysqli_*或PDO，因为此扩展程序自PHP 5.5.0起已弃用，并将在未来。

Mysql动态旋转和分组

1 个答案: