Question

我有一个包含一些用户数据的表，第二个包含用户属性数据。这些属性总是2，我知道他们的名字。我需要一个查询来检索单个结构中的所有内容。但是，我无法改变数据库架构。

这是我的数据库的简化版本：

USER

+-------------------+--------------+------+-----+---------+-------+
| Field             | Type         | Null | Key | Default | Extra |
+-------------------+--------------+------+-----+---------+-------+
| username          | varchar(64)  | NO   | PRI | NULL    |       |
| name              | varchar(100) | YES  |     | NULL    |       |
+-------------------+--------------+------+-----+---------+-------+

USER_PROPERTIES

+-----------+--------------+------+-----+---------+-------+
| Field     | Type         | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+-------+
| username  | varchar(64)  | NO   | PRI | NULL    |       |
| propName  | varchar(100) | NO   | PRI | NULL    |       |
| propValue | text         | NO   |     | NULL    |       |
+-----------+--------------+------+-----+---------+-------+

所以，举例来说，这个数据：

USER

username         name
1                User1
2                User2

USER_PROPERTIES

username         propName         propValue
1                status           "At work"
1                picture          "pict1.jpg"
2                status           "Busy"
2                picture          "pict2.jpg"

我需要以下结果：

username         name             STATUS          PICTURE
1                User1            "At work"       "pict1.jpg"
2                User2            "Busy"          "pict2.jpg"

我在互联网上做了一些研究，显然这是通过PIVOT实现的，但MySQL不包含这个功能。通过这里的答案：MySQL pivot table，我可以设法得到这个：

select ou.username, 
    case when (oup.propName='status') then oup.propValue end as 'STATUS',
    case when (oup.propName='picture') then oup.propValue end as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username;

username         name             STATUS          PICTURE
1                User1            "At work"       null
1                User1            null            "pict1.jpg"
2                User2            "Busy"          null
2                User2            null            "pict2.jpg"

结果分为两个不同的部分。如果我按用户名对结果进行分组，我会将PICTURE数据始终显示为空：

select ou.username, 
    case when (oup.propName='status') then oup.propValue end as 'STATUS',
    case when (oup.propName='picture') then oup.propValue end as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username
group by oup.username;

username         name             STATUS          PICTURE
1                User1            "At work"       null
2                User2            "Busy"          null

我错过了什么？感谢。

编辑：https://stackoverflow.com/users/1529673/strawberry给出了解决方案：

select ou.username, 
    MAX(case when (oup.propName='status') then oup.propValue end) as 'STATUS',
    MAX(case when (oup.propName='picture') then oup.propValue end) as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username;

Answer 1

https://stackoverflow.com/users/1529673/strawberry给出了解决方案：

select ou.username, 
    MAX(case when oup.propName='status' then oup.propValue end) as 'STATUS',
    MAX(case when oup.propName='picture' then oup.propValue end) as 'PICTURE'
from User ou
Join User_Properties oup
On ou.username = oup.username;

MySQL透视行和列

1 个答案: