Question

我有两个名为tableFileTemp2和tableFile的表。我需要一个明确的计算机列表，将path和file列合并到tableFile表path列...

tableFileTemp2 //来源

+-------+----------+--------+-------+
| host  |   path   |  date  | file  |
+-------+----------+--------+-------+
| comp1 | c:\      | xydate | x.exe |
| comp1 | c:\Temp\ | xydate | x.exe |
| comp2 | c:\win\  | xydate | y.exe |
| comp2 | c:\win\  | xydate | z.exe |
+-------+----------+--------+-------+

tableFile //这是结果，显然每台机器都复制了第一个路径+文件

+-------+---------------------------------------------------+--------+------+
| host  |                     path                          |  date  | file |
+-------+---------------------------------------------------+--------+------+
| comp1 | c:\x.exe<br>c:\x.exe<br>c:\Temp\x.exe<br>         | xydate | null |
| comp2 | c:\win\y.exe<br>c:\win\y.exe<br>c:\win\z.exe<br>  | xydate | null |
+-------+---------------------------------------------------+--------+------+

tableFile //预期结果

+-------+----------------------------------+--------+------+
| host  |                path              |  date  | file |
+-------+----------------------------------+--------+------+
| comp1 | c:\x.exe<br>c:\Temp\x.exe<br>    | xydate | null |
| comp2 | c:\win\y.exe<br>c:\win\z.exe<br> | xydate | null |
+-------+----------------------------------+--------+------+

我的代码：

for (int s = 0; s < tableFileTemp2.Rows.Count; s++)
{
    if (tableFile.Rows.Count != 0)
    {
        for (int t = 0; t < tableFile.Rows.Count; t++)
        {
            if (string.Equals(tableFile.Rows[t][0].ToString(), tableFileTemp2.Rows[s][0].ToString(), StringComparison.OrdinalIgnoreCase))
            {
                tableFile.Rows[t][1] = tableFile.Rows[t][1].ToString() + tableFileTemp2.Rows[s][1].ToString() + tableFileTemp2.Rows[s][3].ToString() + "<br>";
                break;
            }
            else if (t == (tableFile.Rows.Count - 1))
            {
                tableFile.Rows.Add(tableFileTemp2.Rows[s][0].ToString(), (tableFileTemp2.Rows[s][1].ToString() + tableFileTemp2.Rows[s][3].ToString() + "<br>"), tableFileTemp2.Rows[s][2], null);
            }
        }
    }
    else
    {
        tableFile.Rows.Add(tableFileTemp2.Rows[s][0].ToString(), (tableFileTemp2.Rows[s][1].ToString() + tableFileTemp2.Rows[s][3].ToString() + "<br>"), tableFileTemp2.Rows[s][2], null);
    }
}

Answer 1

正如您在评论中所说，您仍然拥有数据来自的原始CSV。我们可以用LINQ做到这一点。

+-------+----------+--------+-------+
| host  |   path   |  date  | file  |
+-------+----------+--------+-------+
| comp1 | c:\      | xydate | x.exe |
| comp1 | c:\Temp\ | xydate | x.exe |
| comp2 | c:\win\  | xydate | y.exe |
| comp2 | c:\win\  | xydate | z.exe |
+-------+----------+--------+-------+

然后代码看起来像。

var results =
    from thing in
        (from line in tableFileCSV.Split(new[] { "\r\n", "\n" }, StringSplitOptions.None)
         let row = line.Split(',')
         select new
         {
             Host = row[0],
             Path = row[1] + row[3] + "</br>",
             Date = row[2],
             File = row[3] // <- Are you sure you want this to be null and not the file value?
         })
    group new { thing.Path, thing.Date, thing.File } by new { thing.Host } into g
    select new
    {
        Host = g.Key.Host,
        Path = g.Select(i => i.Path).Aggregate((a, b) => a + b),
        Date = g.Select(i => i.Date).FirstOrDefault(),
        File = "File",
    };

// If you want to get a look at it.
foreach (var item in results)
{
    Console.WriteLine("{0} {1} {2} {3}", item.Host, item.Path, item.Date, item.File);
}

tableFileCSV是CSV中的原始数据。

然后可以将其传递到数据表中。

var dt = new DataTable();
dt.Columns.Add("Host"); 
dt.Columns.Add("Path"); 
dt.Columns.Add("Date"); 
dt.Columns.Add("File"); 
foreach (var item in results) 
{   
    dt.Rows.Add(item.Host,item.Path,item.Date,item.File);                 
}

为什么第一个匹配在循环中重复？

1 个答案: