Question

我在填充下拉列表时遇到困难

这是 add.php视图

  <?php
  echo form_open('',$attributes);?>

  <table cellpadding="0" cellspacing="0" class="user_table biz_table">
<tr>
  <th>City:</th>
    <td>
     <select id="city_id" name="city_id">
    <?php foreach($cities as $c){ ?>

         <option value="<?php echo $c->id; ?>" <?php if ($biz['city_id']===$c->id){ 
             >selected="selected"<?php }?> ><?php echo $c->name?></option>

    <?php }?>

     </select>
    <tr>    
     <th>Neighborhood:</th>
  <td>
  <select id="district_id" name="district_id">
    <option value=""></option>
     <?php foreach($districts as $d){ ?>

      <option value="<?php  echo $d->id; ?>" <?php if($biz['district_id']===$d->id){?
          >selected<?php }?>><?php  echo $d->name?></option>
         <?php }?>

  </select>
<span style="color: red;"><?php echo form_error('district_id'); ?></span>
 </td>
</tr>

这是javasript。我相信它用于刷新页面!!!!!

<script type="text/javascript">

var cities = [];
<?php foreach($cities as $city):?>
   cities[<?php echo $city->id ?>] = '<?php echo $city->name?>';
<?php endforeach;?>

$(function(){
   $('#city_id').change(function(){
  city_id=$('#city_id').val();
  Utils.loadAction('#district_id','/biz/get_children/'+city_id+'/city');
});

$('#catid_1').change(function(){
  catid_1=parseInt($('#catid_1').val());
  Utils.loadAction('#subcat','/biz/get_children/'+catid_1+'/category');
});

<?php if(isset($biz['rating']) && $biz['rating']>0):?>
  var biz_rating=parseInt('<?php $biz['rating']?>');
  if(biz_rating>0)
  {
    $('#rating').val(biz_rating);
    $('.star-'+biz_rating).addClass('active-star');
    $(".rating-hint").html($(".star-"+biz_rating).attr("title"));
  }
<?php endif;?>

});

这是控制器biz.php

     Class Biz extends CI_controller
     {

     function __construct()
      {
    parent::__construct();
      }



     public function add()
     {

    if(!$this->tank_auth->is_logged_in())
    {
        redirect('/ucp/login/');
    }
    $this->load->helper('form');
    $biz=$this->get_form_data();
    $with_review=1;
    if(!empty($_POST)&&!isset($_POST['with_review']))
    {
        $with_review=0;
    }




    //validating
    $this->load->library('form_validation');
    $this->form_validation->set_error_delimiters('','');
    $this->form_validation->set_rules('city_id', 'City',  
          'trim|required|intval|max_length[20]|callback_city_check');
    $this->form_validation->set_rules('district_id', 'District', 
          'trim|intval|max_length[20]|callback_city_check');

    if($this->form_validation->run())
    {
        //get validated data
        $biz=$this->get_form_data();


        }


        //save business
        $this->load->model('bizs');
        $bizid = $this->bizs->add($biz);



        redirect('/biz/'.$bizid);

    }

    //get cities
    $this->load->model('catsAndCities','cc');
    $this->cc->set_table_name('city');
    $data['cities'] = $this->cc->get_top();

    if(!$biz['city_id'])
    {
        //$city=$data['cities'][0];
        $biz['city_id'] = 0;
        if($this->tank_auth->get_user_city())
            $biz['city_id']=$this->tank_auth->get_user_city()->id;

    }

    $data['districts']=$this->cc->get_children($biz['city_id']);


            //$data['districts']=$this->cc->get_children($biz['city_id']);

    //$data['districts']=$this->cc->get_children();
    $data['biz']=$biz;
    $data['heading']="Add A Business";

    $this->load->view('biz/add',$data);

          }

控制器biz.php

内的

get_form_data（）

private function get_form_data()
{
$biz=array(
  'city_id'=>$this->input->post("city_id"),
  'district_id'=>$this->input->post("district_id")
    );
return $biz;
}

获取图书馆/ tank_auth.php中的用户城市

function get_user_city()
{

    $this->ci->load->model('catsAndCities','cc');
    $this->ci->cc->set_table_name('city');
    $this->ci->load->helper('cookie');
    if($cookie_v = get_cookie($this->ci->config-
        >item('default_city_cookie_name'),TRUE))
    {

        if($city = $this->ci->cc->get($cookie_v,'slug'))
        {
            if($city->parent_id == 0)
            {
                $this->city = $city;
                return $city;
            }
        }
    }
    $city = array_shift($this->ci->cc->get_top());

    $this->city = $city;
    return $city;
     }

这两个是模型catsandcities.php

public function get_all()
{


    $data=array();
    $this->db->order_by('parent_id','asc');
    $this->db->order_by('`order`','asc');
    $query=$this->db->get($this->table_name);
    foreach($query->result() as $row)
    {

        $data[$row->id]=$row;
    }

    return $data;

}

public function get_children($parent_id)
{
    $children=array();
    if($items=$this->get_all())
    {
        foreach($items as $i)
        {
            if($i->parent_id === $parent_id)
            {
                $children[]=$i;
            }
        }
    }
    return $children;
}

文件位于https://github.com/leungxd/upble

由于

Answer 1

我不完全理解你的问题，但看看代码，我看到做一个简单的任务很麻烦。我的建议：

使用form helper生成下拉菜单
简化您访问数据的方式并委派控制器仅检索此类数据
尽可能少地放在视图中，不要在那里做任何逻辑

1 - 使用表单助手

<?= form_dropdown('city_id', $cities, 'default') ?>

这将为您生成select和options html代码。只需确保它在form_open（）函数内。

2 - 简化访问数据的方式......

以你的方法为例：

public function get_children($parent_id)
{
    $children=array();
    if($items=$this->get_all())
    {
        foreach($items as $i)
        {
            if($i->parent_id === $parent_id)
            {
                $children[]=$i;
            }
        }
    }
    return $children;
}

不是从表中加载所有记录，而是在查询级别上按父级过滤：

public function get_children($parent_id)
{
    $this->db->where('id_parent', $parent_id);
    $query = $this->db->get($this->table_name);

    $result = $query->result();
    return $result;
}

3 - 不要在视图上添加逻辑

我建议在你的控制器中创建一个方法，在这个方法中返回一个json编码的对象，然后用jquery的ajax请求调用它，然后填充子下拉列表：

public function get_children($parent_id)
{
    $this->db->where('id_parent', $parent_id);
    $query = $this->db->get($this->table_name);

    $result = $query->result();

    if(empty($result) == FALSE) {
        return json_encode($result);
    }

    return NULL;
}

因此，每当您调用yoururl / controller / get_children并通过帖子传递父ID时，您将以json编码的方式获取该城市的子项，您可以使用jquery来操作数据客户端而不是让数以千计的记录膨胀你的HTML。

阅读stackoverflow的指南，否则您将无法获得太多帮助，并尝试清楚您要解决的问题。祝你好运！

Answer 2

我刚添加了一个子域名，它解决了这个问题。

感谢

在codeigniter中填充下拉列表

2 个答案: