查看文件:
"<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
function getval(get)
{
var id = get.value;
//alert(id);
$.ajax({
type : "POST",
url :"/admin/ajax",
data :{id:id},
success:function(data){
alert(data);
//$('#sub_category').html(data);//window.location = "<?php echo site_url('admin/examdetails/form'); ?>"
}
});
}
</script>
Controller:
function ajax(){
$id = $_POST['id'];
// print_r($id);
$this->load->model('admin_model');
$query =$this->admin_model->get_sub_details($id);
echo '<select name="sub_category" id="sub_category">';
//print_r($query->result_array());
//exit();
foreach($query->result_array() as $row){
$name = $row['s_name'];
$id = $row['s_id'];
echo'<option name="category" id="category" value="'.$id.'">';
echo $name;
echo'</option>';
echo'</select>';
}
}
如何在视图中打印Dropdown
?
答案 0 :(得分:0)
只需使用您的ajax请求从控制器获取JSON数据,过滤该json数据并收集javascript变量并将其传递到同一视图中定义的子类别中。
希望这是有道理的:
IN控制器:
// Send only JSON data on request
function ajax(){
$id = $_POST['id'];
// print_r($id);
$this->load->model('admin_model');
$query =$this->admin_model->get_sub_details($id);
$result = $query->result_array();
// Send Data only in JSON Format
$this->output
->set_content_type("application/json")
->set_output(json_encode(array('data'=>$result)));
}
在视图中:
<select name="sub_category" id="sub_category"></select>
IN JS:
//send ajax request to get the JSON data for Categories
$.ajax({
type : "POST",
url :"/admin/ajax",
dataType: 'json',
data :{id:id},
success:function(response){
var _option = '';
// Filter JSON data and Collect in Option
$.each(resonse.data, function(i, data) {
_option += '<option value="'+data.s_id+'">'+data.s_name+'</option>';
});
// Add Options to Sub Category
$('#sub_category').html(_option);
}
});
同时阅读代码中的应用注释以了解它。