Question

我现在正在使用MATLAB来计算具有CSI的MIMO信道的容量。因此，我需要使用水填充来获得功率水平....但是我有一些问题，结果图是向下凹的。任何人都可以给我一些建议，我做错了吗？

clear 
nr=2;
nt=2;
minN = min(nr,nt);
transmitSNR = -20;

for k=1:21     %- set the value of Po/No in dB 
for m=1:1000

    for t=1:nr
        for y=1:nt
             a=1/sqrt(2)*randn(nr,nt);
             b=1/sqrt(2)*randn(nr,nt);
             H=a+1i*b;  %- complex form of H 
         end
    end        
   %- Hr=R^1/2*H;        
    [S V D]=svd(H);
    cap(m)=0;
    for n=1:1:minN        
        lambda(n) = V(n,n);
    end

        [lambda L] = sort(lambda,'descend');
        lambda = lambda(find(lambda > 0));      % ignoring non-positive eigenvalues
        pl = -1;
        try
            while (min(pl) < 0)
                mu = (transmitSNR + sum(1 ./ lambda)) / length(lambda);
                pl = mu - 1 ./ lambda;
                lambda = lambda(1:end-1);
            end
        catch
            disp('There exists no water filling level for the input eigenvalues. Check your data and try again')
        end
        pl = [pl; zeros(length(L) - length(pl), 1)]; % assigning zero power for weak eigen-modes 
        pl(L) = pl;

        for n=1:1:minN
             cap(m) = cap(m) + sum( log2(1 + pl(n).*lambda));

        end
    end           

capacity(k)=mean(cap);
SNR(k) = transmitSNR;
transmitSNR = transmitSNR+2;    
end
plot (SNR,capacity,'d-m'); hold on;
title('Graph of SNR & channel capacity');
xlabel('SNR,dB');
ylabel('Channel capacity');

Answer 1

我对上述问题的解决方案是：

SNR_dB=-20; % Here is your SNR in dB
transmitSNR=10.^(SNR_dB./10); % Here is the conversion

在MATLAB中使用CSI的MIMO信道

1 个答案: