Question

import java.util.Scanner;

public class ExponentExperiment
{
    public static void main(String [] args)
    {
        int numberOne;
        int B;
        int C;
        Scanner keyBoard = new Scanner(System.in);
        System.out.println("Enter an Integer");
        numberOne = keyBoard.nextInt();
        jordan(numberOne, B);
        carter(numberOne, B, C);
        System.out.println(numberOne + " squared is " + B);
        System.out.println(numberOne + " cubed is " + C);
    }
    public static int jordan(int numberOne, int B)
    {
        B = numberOne * numberOne;
    return B;

    }
    public static int carter(int numberOne, int B, int C)
    {
            C = B * numberOne;
    return C;

    }

}

错误：

H：\ ExponentExperiment.java：13：变量B可能尚未初始化约旦（numberOne，B）; ^ H：\ ExponentExperiment.java：14：变量C可能尚未初始化卡特（numberOne，B，C）; ^ 2个错误

工具已完成，退出代码为1

Answer 1

为什么不直接使用您的返回值？

import java.util.Scanner;

public class ExponentExperiment
{
    public static void main(String [] args)
    {
        int numberOne;
        int b = 0;
        int c = 0;
        Scanner keyBoard = new Scanner(System.in);
        System.out.println("Enter an Integer");
        numberOne = keyBoard.nextInt();
        b = jordan(numberOne);
        c = carter(numberOne, b);
        System.out.println(numberOne + " squared is " + b);
        System.out.println(numberOne + " cubed is " + c);
    }
    public static int jordan(int numberOne)
    {
        return (numberOne * numberOne);
    }

    public static int carter(int numberOne, int b)
    {
            return (b * numberOne);
    }
}

Answer 2

在Java中，简单类型的变量是按值传递的，所以它永远不会起作用。请参阅：Is Java "pass-by-reference" or "pass-by-value"?

Answer 3

你有int B;和int C;在主要方法的顶部，执行

  int B = 0; 
  int C = 0;

所以他们被初始化了。

在新方法中初始化变量

3 个答案: