我如何在mysql中获得第二个最大ID？

Question

如何在mysql中获得第二个最大ID？

请看下面的代码和图片：

SET FOREIGN_KEY_CHECKS=0;

-- ----------------------------
-- Table structure for `a`
-- ----------------------------
DROP TABLE IF EXISTS `a`;
CREATE TABLE `a` (
  `id` int(11) NOT NULL auto_increment,
  `name` varchar(30) default NULL,
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=8 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of a
-- ----------------------------
INSERT INTO `a` VALUES ('1', 'jimy');
INSERT INTO `a` VALUES ('7', 'khon');
INSERT INTO `a` VALUES ('3', 'tina');
INSERT INTO `a` VALUES ('4', 'kelvin');
INSERT INTO `a` VALUES ('5', 'ricky');

Answer 1

使用limit子句：

select *
from a
order by id desc
limit 1, 1

Answer 2

我喜欢Gordon Linoff的回答，同时提供了我丑陋的条款：

select min(id) as id from 
       (select * from a order by id desc limit 2) as temp_table;

Answer 3

试试这个：

select max(id) from a where id != (select max(id) from a)

Answer 4

获取第二个最高工资的最简单方法第n个工资

select 
 DISTINCT(salary) 
from employee 
 order by salary desc 
limit 1,1

注意：

limit 0,1  - Top max salary

limit 1,1  - Second max salary

limit 2,1  - Third max salary

limit 3,1  - Fourth max salary