Question

我有这个查询：

BEGIN 
  DROP TABLE IF EXISTS `tblquota`;
CREATE TABLE IF NOT EXISTS tblquota (id INT AUTO_INCREMENT PRIMARY KEY) AS
     SELECT c.id as user_id
         , c.`email`
         , h.`packageid` as pack_id
         , p.`name` as pack_name
         , max(CASE 
             WHEN `name` = "Basic" THEN '100'
             WHEN `name` = "Silver" THEN '100'
             WHEN `name` = "Gold" THEN '100'
                 ELSE '10'
            END) as quota
     FROM `tblclients` c
     LEFT JOIN `tblhosting` h ON c.id = h.userid 
     INNER JOIN `tblproducts` p ON h.packageid = p.id 
     ORDER BY c.id;
END

在这种情况下，查询将仅获得一个客户的最大值。我想获得每个客户的价值。

表客户：

id | email          | status
----------------------------
1  | user1@mail.com | Active
2  | user2@mail.com | Inactive
3  | user3@mail.com | Active

表 tblhosting

id | userid | packageid | domainstatus 
------------------------------------------------
1  | 1      | 3         | Active
2  | 1      | 2         | Active
3  | 2      | 1         | Active
4  | 2      | 2         | Active
5  | 2      | 3         | Inactive
6  | 3      | 1         | Active

表 tblproducts

id | name 
-----------
1  | Basic
2  | Silver
3  | Gold

我希望得到这样的结果：

id | user_id | email          | pack_id | pack_name | quota
-----------------------------------------------------------
1  | 1       | user1@mail.com | 3       | Gold      | 1000
2  | 2       | user2@mail.com | 2       | Silver    | 100
3  | 3       | user3@mail.com | 1       | Basic     | 10

Answer 1

您正在寻找的是Max OVER (PARTITION BY user_id)

获取每个ID的最大值

1 个答案: