Question

我试图为字母表中的每个字母绘制一个图表（仅用2个测试）。我从plot_letter func返回的数据是（'LETTER'，[年份范围]，[数据值每年一个]）。最后我的for循环调用func，检索数据并为每个创建单独的绘图。我如何将所有图表放在一个图上？

import csv
import matplotlib.pyplot as plt 

start = 1880
stop = 1999
years = range(start, stop+1)
alphabet=['A','C']#,'D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']

def plot_letter(i):
year_values = []
for year in years:
    filename = 'yob' + str(year) + '.txt'
    z = open(filename)      
    c = 0
    d = 0
    for line in z:
        y = line.strip().split(',')
        y.remove(y[1])
        c += int(y[1])
        if i in y[0]:
            d += int(y[1])
    year_values.append(float(d)/float(c))           
return i,years, year_values

for i in alphabet:
    data = zip(plot_letter(i)[1], plot_letter(i)[2])
    x_val = [x[0] for x in data]
    y_val = [x[1] for x in data]
    plt.plot(x_val, y_val)  
    plt.show()

Answer 1

这段代码：

for i in alphabet:
    data = zip(plot_letter(i)[1], plot_letter(i)[2])
    x_val = [x[0] for x in data]
    y_val = [x[1] for x in data]
    plt.plot(x_val, y_val)  
    plt.show()

多次调用show()。

如果你想要一个有多行的图，只需将它移出循环：

for i in alphabet:
    data = zip(plot_letter(i)[1], plot_letter(i)[2])
    x_val = [x[0] for x in data]
    y_val = [x[1] for x in data]
    plt.plot(x_val, y_val)  
plt.show()

在单个图上绘制多个图

1 个答案: