我创建了一个php页面,其中我想获得总行数,但它给我的结果为零,我如何总结php中的行数,这是我的代码:
<?
$recepients=0;
$count=count($_POST['events']);
for($i=0; $i<$count; $i++){
$select="select b.first_name AS first_name,b.last_name AS last_name from buyers b,registrations r where b.buyer_id=r.buyer_id and r.event_id='".$_POST['events'][$i]."' group by r.buyer_id";
$res = $GLOBALS ['mysqli']->query ($select) or die ($GLOBALS ['mysqli']->error . __LINE__);
$record=mysqli_num_rows($res);
}
echo $recepients+=$record;
?>
答案 0 :(得分:2)
尝试添加到循环中
<?
$recepients=0;
$count=count($_POST['events']);
for($i=0; $i<$count; $i++){
$select="select b.first_name AS first_name,b.last_name AS last_name from buyers b,registrations r where b.buyer_id=r.buyer_id and r.event_id='".$_POST['events'][$i]."' group by r.buyer_id";
$res = $GLOBALS ['mysqli']->query ($select) or die ($GLOBALS ['mysqli']->error . __LINE__);
$record=mysqli_num_rows($res);
$recepients = $recepients + $record;
}
echo $recepients;
?>
答案 1 :(得分:1)
<?
$recepients=0;
$count=count($_POST['events']);
for($i=0; $i<$count; $i++){
$select="select b.first_name AS first_name,b.last_name AS last_name from buyers b,registrations r where b.buyer_id=r.buyer_id and r.event_id='".$_POST['events'][$i]."' group by r.buyer_id";
$res = $GLOBALS ['mysqli']->query ($select) or die ($GLOBALS ['mysqli']->error . __LINE__);
$record = mysqli_num_rows($res);
$recepients += $record; // i think you're missing this
}
echo $recepients; // edited - forgot to edit this one.
?>
我想你只是错过了一行代码。
答案 2 :(得分:1)
计算应在循环内完成,
$recepients = 0;
for($i=0; $i<$count; $i++){
$select="select b.first_name AS first_name,b.last_name AS last_name from buyers b,registrations r where b.buyer_id=r.buyer_id and r.event_id='".$_POST['events'][$i]."' group by r.buyer_id";
$res = $GLOBALS ['mysqli']->query ($select) or die ($GLOBALS ['mysqli']->error . __LINE__);
$record=mysqli_num_rows($res);
$recepients += $record;
}
echo $recepients;