我有一个像
这样的查询SELECT row1, row2
FROM (
SELECT b.row21, COUNT(b.row21) AS hits
FROM table2 AS b
WHERE b.row22 = 'foo' OR b.row22 = 'bar'
GROUP BY b.row21
HAVING hits = 2
) AS b
INNER JOIN table1 AS a ON (b.row21 = a.row1)
WHERE row2 = 123
LIMIT 10
现在显然,结果首先受到额外WHERE
的限制,最后受到LIMIT
的限制。
那么如何检索子查询返回的行数而不需要单独执行呢?
答案 0 :(得分:1)
您可以使用变量在MySQL中执行此操作:
SELECT row1, row2, @rn as numrows
FROM (
SELECT b.row21, COUNT(b.row21) AS hits, @rn := @rn + 1
FROM table2 b cross join
(select @rn := 0) const
WHERE b.row22 = 'foo' OR b.row22 = 'bar'
GROUP BY b.row21
HAVING hits = 2
) AS b
INNER JOIN table1 AS a ON (b.row21 = a.row1)
WHERE row2 = 123
LIMIT 10;
您冒着MySQL 可以以非常不同的方式重写查询的风险,这可能会避免生成某些行。一些SQL编译器足够聪明,可以做到这一点。我不认为MySQL那么聪明。