Question

我遇到构造函数问题，我需要创建2个构造函数。 1.无参数构造函数将对象设置为安全的空状态。 2.双参数构造函数

当我为对象变量赋值时，我收到错误。

CreditCard.cpp: In constructor âCreditCard::CreditCard()â:
CreditCard.cpp:8:11: error: invalid use of member (did you forget the â&â ?)
CreditCard.cpp: In constructor âCreditCard::CreditCard(long long int, char*)â:
CreditCard.cpp:15:11: error: invalid use of member (did you forget the â&â ?)
CreditCard.cpp: In member function âlong long int CreditCard::number() constâ:
CreditCard.cpp:32:12: error: argument of type âlong long int (CreditCard::)()constâ does not match âlong long intâ

1.CreditCard（）;

CreditCard::CreditCard() {
   number=0;
   strcpy(holder,"ABCD");
   balances=0;
}

2。 CreditCard（2个参数）

CreditCard::CreditCard(long long num,char h[21]) {
   number=num; 
   strcpy(holder,h);
}

第3。第3次错误

long long CreditCard::number() const {

   return  number;
}

Class（在头文件中）

class CreditCard {
   long long int nubmer;
   char holder[21];
   double balances;

   public:
     /*declarations of constuctors */
     CreditCard();
     CreditCard(long long num,char h[21]);

     void charge(double c);
     void pay(double p);
     long long number() const;
     double balance() const;
     const char* name() const;
};

更新：与成员变量和函数（名称）混淆

Answer 1

long long int nubmer;

仔细看看那条线。

long long CreditCard::number() const {

   return  number;
}

此函数声称它返回long long，但实际上它会尝试返回函数。这应该如何运作？

C ++错误，类和构造函数

1 个答案: