Question

我是python的新手，我真的很难找到解决这个问题的方法。

我只是不明白为什么我需要在列表中只包含整数，因为它们应该支持多种数据类型。

我有一个非常简单的帐户注册字段输入系统，我只是无法将这些项目添加到列表中。

非常感谢任何帮助。我已经包含了我的代码和收到的消息。

useraccounts = {}
group = []



forename = input('Forename: ')
surname = input('Surname: ')
DOB = input('DOB: ')
stu_class = input('Class: ')

group['forename'] = forename
group['surname'] = surname
group['dob'] = DOB
group['class'] = stu_class

group.append(user accounts)

这是错误消息：

Traceback (most recent call last):
  File "/Users/admin/Documents/Homework/Computing/testing/testing.py", line 11, in <module>
    group['forename'] = forename
TypeError: list indices must be integers, not str

Answer 1

你想要的是dictionary：

group = {}

group['forename'] = forename
group['surname'] = surname
group['dob'] = DOB
group['class'] = stu_class

在原始代码中useraccounts保留一个空的dict，您只需将其添加到列表中即可。如果您想将group添加到useraccounts：

useraccounts['key'] = group

Answer 2

您希望group成为dict，useraccounts成为list。你有他们倒退，以及追加：

useraccounts = []   # <-- list
group = {}          # <-- dict

forename = input('Forename: ')
surname = input('Surname: ')
DOB = input('DOB: ')
stu_class = input('Class: ')

group['forename'] = forename
group['surname'] = surname
group['dob'] = DOB
group['class'] = stu_class

useraccounts.append(group)   # <-- reversed. this will append group to useraccounts

如上所述，您试图将useraccuonts（空列表）附加到group，dict没有append方法

Answer 3

group是一个列表，它不能采用字符串索引。看起来你想要使用字典：

useraccounts = []
group = {}

group['forename'] = forename
group['surname'] = surname
group['dob'] = DOB
group['class'] = stu_class

useraccounts.append(group)

请注意，您可能希望useraccounts成为此处的列表;您的代码尝试在.append()对象上调用group ..

或将键和值直接内联到字典定义中：

useraccounts.append({
    'forename': forename,
    'surname': surname,
    'dob']: DOB,
    'class': stu_class})

list indices必须是整数，而不是str 6

3 个答案: