Question

我有一个由Object预先填充的表单。框架：金字塔，IDE：PyCharm

在页面上，我有额外的字段供用户添加其他电话号码和电子邮件。例如，单个电话对象{tag：work，value：555}将被推入person对象内的phones []数组中。然后我需要将新信息发送回服务器。

的jQuery

// Person
var person = {
    username : profileData.username,
    firstName : "",
    lastName : "",
    phones : [],
    emails : [],
    organization : "",
    title : ""
}

// Original Profile
person.firstName = $('#profile-firstname').val();
person.lastName  = $('#profile-lastname').val();
person.organization = $('#profile-company').val();
person.title  = $('#profile-title').val();

// Added Profile
var phoneObjs   = {};
var emailObjs   = {};
var extraPhones = [];
var extraEmails = [];
var addedPhones = $('.added_phone');
var addedEmails = $('.added_email');

addedPhones.each( function(i) {
    //console.log(i);
    var tag = $(this).children("label").text();
    var value = $(this).children("input").val();
    phoneObjs = $(this).map(function(i,el) {
        var $el = $(el);
        return {
            tag: tag,
            value:value
        };
    }).get();
    person.phones.push(phoneObjs);
    console.log(phoneObjs);
});

的Python

def save_profile(self):
    success_msgs = ['Saved! Worry not, nothing sent to the NSA... as far as we know', "Profile Saved, doesn't it feel great to be updated?"]
    error_msgs = ['Internets are clogged up, our monkeys are checking it out', 'Hmm, everything look correct below?', "A BUG! Probably in our code, we're checking it out"]
    try:
        json = self.request.json_body
        first_name = str(json['firstName'])
        last_name = str(json['lastName'])
        organization = str(json['organization'])
        title = str(json['title'])
        phones = (json['phones'])
        emails = (json['emails'])
        self.profiles.update(firstName=first_name, lastName=last_name, organization=organization, title=title, emails=emails, phones=phones)
        #print phones
        value = {'result': 'success', 'message': random.choice(success_msgs)}
    except Exception, err:
        print err
        value = {'result': 'error', 'message': random.choice(error_msgs)}

    #returns a json response
    return self.respond(value)

profile.update

if tools.not_blank(phones):
        lst = phones
        cnt = len(lst)
        current = profile.phones
        for x in xrange(cnt):
            o = lst[x]
            #key = o.get("key", o.get("guid", None))
            lbl = o["label"]
            tag = o.get("tag", None)
            c = [c for c in current if c.label == lbl]
            c = c[0] if len(c) > 0 else None
            if c:
                m, k = self.codex.decode_composite(c.id)
                if tools.not_blank(tag):
                    tag = tag.lower().title()
                    if c.tag != tag:
                        c.tag = tag
                        self.get_query("UPDATE member_phone SET Type = @tag WHERE ID = @id;", {"tag": tag, "id": k}).update()
            else:
                #create a new email address for this member
                self.members.register_phone_number(member=member, telephone=lbl, tag=tag)

    if tools.is_blank(remove):
        return profile

IDE将抛出“list indices必须为整数，而不是str”错误

有什么想法？不知道这里有什么问题。

self.profiles.update(firstName=first_name, lastName=last_name, organization=organization, title=title, emails=emails, phones=phones)

带有添加字段的表单会在此处创建正确的对象

enter image description here

Answer 1

当我潜入self.profiles.update（）

时，我的jQuery出了问题。

if tools.not_blank(phones):
        lst = phones
        cnt = len(lst)
        current = profile.phones
        for x in xrange(cnt):
            o = lst[x]
            #key = o.get("key", o.get("guid", None))
            lbl = o["label"]

第一个问题是lbl = 0 [＆＃34;标签＆＃34;]原始开发人员期待电话的标签而不是我传递的价值。

第二件事，我们的iOS开发人员指出我有一个嵌套的数组[[]]没有注意到，所以在jQuery中又回来了：

必须更改：person.phones.push(phoneObjs);至person.phones = phoneObjs;

现在它只为手机返回[]而没有列表错误：）

更新了jQuery

addedPhones.each( function(i) {
    var tag = $(this).children("label").text();
    var value = $(this).children("input").val();
    phoneObjs = $(this).map(function(i,el) {
        var $el = $(el);
        return {
            tag: tag,
            label:value
        };
    }).get();
    person.phones = phoneObjs;
    console.log(phoneObjs);
});

错误：列表索引必须是整数，而不是str

1 个答案: