Question

select datepart(yyyy,hiredate) as Hire_Date_of_Year,jobTitle,count(jobTitle) as Number_Of_Title
from [AdventureWorks2012].[HumanResources].[Employee]
group by jobTitle,hiredate
having hiredate like '2004%'
order by jobtitle asc

以上是我的代码。

我得到的输出就是这个

Hire_Date_of_Year   jobTitle         number_of_Count
2004                Buyer               1
2004                Buyer               1
2004                Buyer               1
2004                Buyer               1
2004                Buyer               1
2004                Buyer               1
2004                Buyer               1
2004                Janitor             1
2004                Janitor             1
2004                Janitor             1
2004                Janitor             1

我正在寻找的输出

Hire_Date_of_Year   jobTitle    number_of_Count
2004            Buyer               7
2004            Janitor             4

先谢谢。

Answer 1

您不应该使用like进行日期比较。这最适用于字符串。这是一种编写所需查询的方法：

select datepart(yyyy, hiredate) as Hire_Date_of_Year,
       jobTitle, count(jobTitle) as Number_Of_Title
from [AdventureWorks2012].[HumanResources].[Employee]
where datepart(yyyy, hiredate) = 2004
group by jobTitle,  datepart(yyyy, hiredate)
order by jobtitle asc;

如果您愿意，datepart(yyyy, hiredate)中的year(hiredate)（或group by如果您愿意）是可选的。如果您不包含它，select需要将年份放在聚合函数中，例如max(datepart(yyyy, hiredate))。

为了提高效率，我将条件移到where子句。您可以在聚合后进行比较（即在having子句中）。但这意味着group by在进行过滤之前的所有年份都在进行分组。

Answer 2

您需要按年份分组，而不是完整日期

SELECT DatePart(yy, hiredate) As Hire_Date_of_Year
     , jobTitle
     , Count(jobTitle) As Number_Of_Title
FROM   [AdventureWorks2012].[HumanResources].[Employee]
WHERE  DatePart(yy, hiredate) = 2004
GROUP
    BY DatePart(yy, hiredate)
     , jobTitle

Answer 3

分组应该是：

group by jobTitle,datepart(yyyy,hiredate)

Answer 4

尝试这样的事情：

SELECT jobTitle, Hire_Date_of_Year,SUM(number_of_Count)
FROM emp
GROUP BY jobTitle, Hire_Date_of_Year

我需要一个SQL Query，按员工分组，年份，

以上是我的代码。

4 个答案: