Question

我的页面中有一个Ajax ModalPopupExtender。当前使用TargetControlId的按钮点击我显示弹出窗口。我需要的是当我点击按钮想要从DB检查一些条件时。如果条件满足我要显示弹出。其他明智的不需要弹出。我怎么能这样做？

 <ajaxToolkit:ModalPopupExtender CancelControlID="btnCancel" BackgroundCssClass="modalBackground" runat="server" ID="PopupExtender"  TargetControlID="btn"  PopupControlID="Panel1"></ajaxToolkit:ModalPopupExtender>

Answer 1

试试这个

protected void Button1_Click(object sender, EventArgs e)
{
     PopupExtender.Show();
}

Answer 2

protected void ButtonSave_Click(object sender, EventArgs e)
    {
     if (MyCondition == true)
        {           
           modalPopUpConfirmation.Show();
        }
     else
        {            
            Label1.Text = "The condition was false, so no modal popup!";
        }
    }

Answer 3

动态调用它。

<!-- Hidden Field -->
<asp:HiddenField ID="hidForModel" runat="server" />

<ajaxToolkit:ModalPopupExtender CancelControlID="btnCancel" BackgroundCssClass="modalBackground" runat="server" ID="PopupExtender"  TargetControlID="hidForModel"  PopupControlID="Panel1"></ajaxToolkit:ModalPopupExtender>

<asp:Button ID="btnShowPopup" runat="server" Text="Save Data"
            OnClick="btnShowPopup_Click" />

代码背后

protected void btnShowPopup_Click(object sender, EventArgs e)
{
  if(Yourcondition)
  {
     PopupExtender.Show();
  }
}

Ajax ModalPopUp窗口根据一定条件

3 个答案: