Question

我在变量中有主键名，我需要找到它们所属的表。 db有很多表，因此不能选择线性搜索。

Answer 1

您可以使用information_schema表。如果主键名是表中的第一列，则可以执行以下操作：

select table_name
from information_schema.columns
where column_name in (<your list here>) and
      ordinal_position = 1;

否则，你必须通过约束来获得你想要的东西。类似的东西：

select kcu.table_name, kcu.column_name
from information_schema.table_constraints tc join
     information_schema.key_column_usage kcu
     on tc.contraint_name = kcu.contraint_name and
        tc.table_name = kcu.table_name
where tc.contraint_type = 'PRIMARY KEY' and
      column_name in (<your list here>);

您也可以使用系统表和视图执行此操作。

Answer 2

你可以试试这个::

SELECT table_name 
FROM information_Schema.columns 
WHERE column_name='dept_id' 
  and ordinal_position = 1;

Answer 3

这应该有用，请尝试一下：

SELECT table_name
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE 
WHERE OBJECTPROPERTY(OBJECT_ID(constraint_name), 'IsPrimaryKey') = 1
AND column_name in (select column_name from <your list here>)

如果将主键约束设置为“CREATE TABLE”查询中第一列以外的任何列，则下面的解决方案将无效。

select table_name
from information_schema.columns
where column_name in (select column_name from <your list here>) and
ordinal_position = 1

例如，如果我们创建这样的表，它将无效：

create table sample1
(
 field1 int,
 field2 int primary key
)

如果我错了，请纠正我。

Answer 4

以下查询根据约束名称

提供表名

select * from INFORMATION_SCHEMA.TABLE_CONSTRAINTS
where CONSTRAINT_NAME ='<ConstraintName>'

Answer 5

要使用主键名称查找表名，请按照以下查询

class data {
  public data: [number, string]; //would be hidden later and accessed by getters for left and right
  constructor (left: number, right: string) {
    this.data=[left, right];
  }
  public equals(rhs: data): boolean {
    return this.data[0] === rhs.data[0] && this.data[1] === rhs.data[1];
  }
}
let theSet = new Set();
let n = 0;
let s = "hello world";
let dat1 = new data(n, s);
theSet.add(dat1);
let dat2 = new data(n, s);
if (theSet.has(dat2)) {
  alert("contains");
} else {
  alert("doesn't contain");
}

Answer 6

从以上答案中得到改善

 select kcu.table_name, kcu.column_name, *
    from information_schema.table_constraints tc join
    information_schema.key_column_usage kcu
    on tc.CONSTRAINT_NAME = kcu.CONSTRAINT_NAME and
    tc.table_name = kcu.table_name
    where tc.CONSTRAINT_NAME = 'PK__DC_INPUT__7EA5540496A9FD5D'

Answer 7

SELECT [TABLE_NAME]
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS
WHERE CONSTRAINT_NAME = 'YourPrimaryKey';

如何在sql中使用主键名查找表名？

7 个答案: