初始化结构内的字符

Question

#define NAMESIZE 20

struct point {
    int x;
    int y;
};

struct rectangle {
    struct point upperleft;
    struct point lowerright;
    char label[NAMESIZE + 1];
};

在我的主要

int main(void) {


    struct rectangle r1;
    r1.upperleft.x = 1;
    r1.upperleft.y = 4;
    r1.lowerright.x = 4;
    r1.lowerright.y = 1;
    strcpy_s(r1.label, NAMESIZE, "hi");




    printf("Upper left: (%d, %d)\n", r1.upperleft.x, r1.upperleft.y);
    printf("Lower Right: (%d, %d)\n", r1.lowerright.x, r1.lowerright.y);
    printf("Name of rectangle: %d", r1.label);
    return 0;
}

我的矩形名称是一个内存地址，我应该如何正确初始化我的结构的字符变量？

Answer 1

    struct rectangle r1 = {{1,4}, {4,1}, "hi"};

    printf("Upper left: (%d, %d)\n", r1.upperleft.x, r1.upperleft.y);
    printf("Lower Right: (%d, %d)\n", r1.lowerright.x, r1.lowerright.y);
    printf("Name of rectangle: %s", r1.label);

Answer 2

这将清除它：memset(&r1.label, 0, sizeof(r1.label))

这是对您所拥有的内容的更正：strcpy_s(&r1.label, NAMESIZE+1, "hi");

&返回“地址”。因此&r1.label是r1中标签的地址。